replace numbers between specific characters using jQuery

Question

I want to replace digits that are exactly next to a-z A-Z 0-9 .-_ linebreak space and they are exactly before a-z A-Z 0-9 .- but not those between 2 spaces or 2 other language characters.

I have strings like :

 1. "www.asdf123asd.com"
 2. "asd123.sdf"
 3. "123.sdf"
 4. "adf 123 asdf"

and I want to change them to :

 1. "www.asdf<b>123</b>asd.com"
 2. "asd<b>123</b>.sdf"
 3. "<b>123</b>.sdf"
 4. "adf 123 asdf"

any suggestion?

regex101.com - have a play with it, sounds like you've got the matching sorted already — scrowler
– scrowler, Commented Mar 20, 2014 at 22:16
this is a sample, I have thousands of rows in tables and I have to do this for all. — SalmanShariati
– SalmanShariati, Commented Mar 20, 2014 at 22:20

anubhava · Accepted Answer · 2014-03-20 22:28:19Z

2

You can use:

repl = string.replace(/(^|[a-z_.-])(\d+)(?=[a-z_.-])/ig, "$1<b>$2</b>");

TESTS:

> "www.asdf123.com".replace(/(^|[a-z_.-])(\d+)(?=[a-z_.-])/ig, "$1<b>$2</b>");
"www.asdf<b>123</b>.com"

> "www.asdf 123 asd.com".replace(/(^|[a-z_.-])(\d+)(?=[a-z_.-])/ig, "$1<b>$2</b>");
"www.asdf 123 asd.com"

> "123.sdf".replace(/(^|[\w.-])(\d+)(?=[\w.-])/g, "$1<b>$2</b>");
"<b>123</b>.sdf"

answered Mar 20, 2014 at 22:28

anubhava

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