How to define new loop function

Question

I have a medhod like this.

def run
  loop do
    sleep 0.1
    # do something
  end
end

And I want to write it like this.

def run
  every 100, :msec do
    # do something
  end
end

How can I write a method like this every?

Rafa Paez · Accepted Answer · 2014-03-23 03:25:30Z

2

def every(quantity, units = :sec)
  # this could be improved but you get the idea
  quantity = quantity / 1000.0 if units == :msec
  loop do 
    sleep quantity
    yield
  end
end

every 100, :msec do
  puts Time.now
end

edited Mar 23, 2014 at 3:25

answered Mar 23, 2014 at 3:11

Rafa Paez

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2 Comments

ironsand Over a year ago

I put sleep quantity; yield inside loop, then it works. Thanks, I couldn't figure out how to use yield.

Rafa Paez Over a year ago

You are welcome. I updated the answer with the loop. Please Vote it up if you like it!

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