Java: How do I remove parameter from querystring

Question

I want to remove some querystring attribute from my url, I tried some regex but didn't get the exact solution for this. Please help me to out of it. eg:

String qString = "category=Popular&code=14290115";
qString = qString .replaceAll("(?<=[?&;])code=.*?($|[&;])",""); 
output: category=Popular&

the above regex is removing the attribute but not removing & symbol. So please suggest me for this.

no... I just want to remove only case parameter. I want this: http://www.domain.com?id=1&start=2&end=5 — Anil Kumar Pandey
– Anil Kumar Pandey, Commented Mar 24, 2014 at 7:43
Why don't you just split into query elements, build a list from the array without the element you want and reconstruct the query string? — fge
– fge, Commented Mar 24, 2014 at 7:49
there is a problem only when case is the last parameter. So maybe, after the replacement, you can test if qString ends with '&' and remove it. — Laura
– Laura, Commented Mar 24, 2014 at 7:49
Oh Sorry... I edited my question. I am using this id=1&case=edit&start=2&end=5 as query string — Anil Kumar Pandey
– Anil Kumar Pandey, Commented Mar 24, 2014 at 7:51

David Ehrmann · Accepted Answer · 2014-03-24 08:00:40Z

4

Don't use a regex for this. It's an utter nightmare because any character could be percent-encoded, e.g. ?foo=bar is exactly the same as ?%66oo=%62ar. Parse the URL, then the query string, then rebuild it. Take a look at URIBuilder and URLEncodedUtils out of the Apache Commons HTTP Client.

edited Mar 24, 2014 at 8:00

answered Mar 24, 2014 at 7:50

David Ehrmann

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2 Comments

Anil Kumar Pandey Over a year ago

Ok Thanks for your suggestion @David, I need to try and check.

Anil Kumar Pandey Over a year ago

I am using URIBuilder and its really helpful. Thanks @David

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