How to convert array pointer into an array argument from template function?

Question

I guess the title is quite confusing, I'll explain my case with some code.

template<uint16_t Len>
void add(const int8_t (&i_array)[Len])
{
  // Do something
}

class Test
{
public:
int8_t* GetName()
{
  return name;
} 

private:
 int8_t name[10] = "myname";
}

int main()
{
 Test mytest;

 add(mytest.GetName()); // Compilation error
}

This code does not compile. The following error is generated : "Error#304 : no instance of function template add matches the argument list"

It seems that the compilator is not able to determine that GetName() return an array of size 10. Is that right ?

How could I call "add" with a pointer on an array ?

Thanks, Nicolas

Kerrek SB · Accepted Answer · 2014-03-24 09:51:01Z

2

Test::GetName returns a pointer, not an array. You cannot bind its result to a function that expects an array reference. However, you could change the signature of GetName to make it return the array (by reference, of course):

int8_t (&GetName())[10] { return name; }

Alternatively you could use a cast, but that would defeat the purpose of the type system.

answered Mar 24, 2014 at 9:51

Kerrek SB

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2 Comments

nbout Over a year ago

Nice, I'll try it now.

Jarod42 Over a year ago

BTW, I suggest to use a typedef to have a simpler syntax.

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