I have an simple question,
How to insert PHP code in PHP variable?
Example :
echo $value = "
bla
bla
<?php $q = "SELECT * FROM BLA BLA"; ?>
";
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6There is a 100% chance of a solution for your application which does not require putting PHP code into a variable the way you demonstrated.Daniel W.– Daniel W.2014-03-24 10:50:35 +00:00Commented Mar 24, 2014 at 10:50
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1echo $value = ' bla bla <?php $q = "SELECT * FROM BLA BLA"; ?> '; like @AwladLiton mentionsDanny– Danny2014-03-24 10:59:15 +00:00Commented Mar 24, 2014 at 10:59
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1It's unclear what you expect that code to do... and it smells like an XY problem: meta.stackexchange.com/questions/66377/what-is-the-xy-problem - my advice: anyone who posts an answer without figuring out what the OP really wants should be downvoted.Karoly Horvath– Karoly Horvath2014-03-24 11:05:52 +00:00Commented Mar 24, 2014 at 11:05
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1 Answer
You can do it using eval()
$test = <<<END
<p> <?php
echo time();
?> </p>
END;
ob_start();
eval("?>$test");
$result = ob_get_clean();
Or an other example from w3s:
<?php
$string = "beautiful";
$time = "winter";
$str = 'This is a $string $time morning!';
echo $str. "<br>";
eval("\$str = \"$str\";");
echo $str;
?>
will print
This is a $string $time morning!
This is a beautiful winter morning!
But be very carefull when you use it, from the php page:
Caution The eval() language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand.
3 Comments
Karoly Horvath
Please... just DON'T.
darkheir
What do you mean? Don't use it?
Vagabond
The link to the manual could give you an idea about eval(). Manual on eval()