assign php variable if checkbox is checked

Question

<input type="checkbox" name="vehicle" value="yes">

If the user checks this, the php variable $vehicle_check should hold the value ="RA" otherwise, the value will hold the default "R". Can I do this without javascript?

I tried:

if(isset($_POST['submitquotes'])){

    $check = $_POST['vehicle'];

    if ($check == 'yes'){
        $vehicle_check = 'RA';
    }
    else{
        $vehicle_check = 'R';
    }
}

This doesn't seem to work.

Can you give some more light on doesn't seem to work ? What exactly you getting in $check ? — Rikesh
– Rikesh, Commented Mar 26, 2014 at 12:33

blue · Accepted Answer · 2014-03-26 12:34:34Z

5

The value of the checkbox is not useful - according to the html spec it'd be submitted only if checked, so check that instead. The following code should be enough:

if ( isset($_POST['vehicle']) ) {
    $vehicle_check = 'RA';
} else {
    $vehicle_check = 'R';
]

answered Mar 26, 2014 at 12:34

blue

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1 Comment

user3391847 Over a year ago

thanks! i am a newbie on php and thanks for the isset part. I thought this is only used when submitting forms. great!

jexact · Accepted Answer · 2014-03-26 12:37:03Z

2

Try this:

$vehicle_check = isset($_POST["vehicle"]) ? "RA" : "R";

answered Mar 26, 2014 at 12:37

jexact

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1 Comment

AdRock Over a year ago

I would have put this

Musa Haidari · Accepted Answer · 2014-03-26 12:38:10Z

1

Try this:

<input type="hidden" value="R"/> <input type="checkbox" name="vehicle" value="RA"/>

If the user checks the checkbox then the value of checkbox overrides the value of hidden field, since they have the same name, but if the checkbox is not checked, then value of hidden field is taken. Remember if you are giving them id give them two different id

answered Mar 26, 2014 at 12:38

Musa Haidari

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