Javascript Dynamic Regex Generation

Question

I want to make my alphanumeric regex dynamic in a way that it takes the allowed special characters with it as an argument by the user. Following is my code ... I am getting quotes error here .... any body can tell me how to go about it ?

function aplhanumeric(value,allowed){

///^[a-z0-9_\-]+$/i
alert(allowed);
if(allowed != ''){
    var regex = new RegExp('/^[a-z0-9_\' + allowed + ']+$/i');
    return (value.match(regex));
}else{
    return (alphaNumericRegex.test(value));
}
}

adeneo · Accepted Answer · 2014-03-27 06:31:24Z

1

You've actually escaped the quote, so you have to escape the escape

var regex = new RegExp("^[a-z0-9_\\" + allowed + "]+$", "i");

edited Mar 27, 2014 at 6:31

answered Mar 27, 2014 at 6:24

adeneo

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4 Comments

adeneo Over a year ago

@Adi's - I just changed it, try it now.

Adi's Over a year ago

I actually want it to accept alphanumeric with allowed characters at any place in the string ?

adeneo Over a year ago

Then why are you using ^ and $ that checks the entire string? Explain exactly what you're trying to do ?

Adi's Over a year ago

I want to pass all allowed special characters in a variable namely allowed which would hold values such as "." then the regex would be built which would allow aplhanumeri with special characters only "" and "."

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