python copy file in local network (linux -> linux) and output

Question

I'm trying to write a script to copy files in my RaspberryPi, from my Desktop PC. Here is my code: (a part)

print "start the copy"   
path_pi = '//192.168.2.2:22/home/pi/Stock/'
file_pc = path_file + "/" + file
print "the file to copy is: ", file_pc

shutil.copy2(file_pc, path_pi + file_pi)

Actually I have this error: (in french)

IOError: [Errno 2] Aucun fichier ou dossier de ce type: '//192.168.2.2:22/home/pi/Stock/exemple.txt'

So, how could I proceed? Must I connect the 2 machines before trying to copy? I have tryed with:

path_pi = r'//192.168.2.2:22/home/pi/Stock'

But the problem is the same. (And file_pc is a variable)

Thanks

Edit: Ok, I found this:

command = 'scp', file_pc, file_pi  
p = subprocess.Popen(command, stdout=subprocess.PIPE)

But no way to have the output... (work with Shell=False)

related: How do I copy a file to a remote server in python using scp or ssh? — jfs
– jfs, Commented Mar 28, 2014 at 11:06

jfs · Accepted Answer · 2014-03-27 20:22:39Z

2

shutil.copy2() works with local files. 192.168.2.2:22 suggests that you want to copy files over ssh. You could mount the remote directory (RaspberryPi) onto a local directory on your desktop machine (sshfs) so that shutil.copy2() would work.

If you want to see the output of a command then don't set stdout=PIPE (note: if you set stdout=PIPE then you should read from p.stdout otherwise the process may block forever):

from subprocess import check_call

check_call(['scp', file_pc, file_pi])

scp will print to whatever places your parent Python script prints.

To get the output as a string:

from subprocess import check_output

output = check_output(['scp', file_pc, file_pi])

Though It looks like scp doesn't print anything by default if the output is redirected.

You could use pexpect to make scp think that it runs in a terminal:

import pipes
import re
import pexpect # $ pip install pexpect

def progress(locals):
    # extract percents
    print(int(re.search(br'(\d+)%[^%]*$', locals['child'].after).group(1)))

command = "scp %s %s" % tuple(map(pipes.quote, [file_pc, file_pi]))
status = pexpect.run(command, events={r'\d+%': progress}, withexitstatus=1)[1]
print("Exit status %d" % status)

edited Mar 27, 2014 at 20:22

answered Mar 27, 2014 at 17:40

jfs

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9 Comments

Guillaume Over a year ago

Thank you, it's work fine. How can I get the callback in a string?

jfs Over a year ago

@Guillaume: I've updated the answer to show how to get subprocess' output

Guillaume Over a year ago

Ok, but: out = check_output(['scp', file_pc, file_pi]) print out Nothing appers, it stay at the first line. In fact, I would like to get the percentage for a progressbar

jfs Over a year ago

@Guillaume: update your question or ask a new one specifically about how to get the percentage from scp command.

jfs Over a year ago

@Guillaume: I've added pexpect-based solution that can extract progress information from scp

|

PabloRosales · Accepted Answer · 2014-03-27 17:39:58Z

2

Do you have SSH enabled? Something like this could help you:

import os
os.system("scp FILE USER@SERVER:PATH")

answered Mar 27, 2014 at 17:39

PabloRosales

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1 Comment

wolfd Over a year ago

While this should work, this isn't really a good idea. Using subprocess.call(['scp', filename, '{}@{}:{}'.format(user, hostname, path)]) would be a bit cleaner. os.system is spawning a shell, and evaluating the text, which is both unnecessary and can lead to easy security vulnerabilities if you are putting any user input into that field.

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