How to sort object array? [duplicate]

With Java SE 8 try something like (untested):

Arrays.stream(p).sorted((p1, p2) -> Integer.compare(p1.number, p2.number)) .collect(Collectors.toList())

Edit

On second thought this might be more efficient in this case, as it doesn't create a new array/ collection:

Arrays.sort(p, (p1, p2) -> Integer.compare(p1.number, p2.number));

Create a class that implements Comparator<Player>, called say PlayerComparator. Implement the interface by creating a compare method that takes two Players. Return a negative number, zero, or a positive number, depending on whether the first Player is considered less than, equal to, or greater than, the second Player.

Then you can create your PlayerComparator and pass it (along with your array) to Arrays.sort.

let your custom class implements Comparable interface and then you can use java Collection to sort your array (Arrays.sort() function)

public class Player implements Comparable<Player> {
   public String player_name;
   public int number;

    @Override
    public int compareTo(Player object) {
        return this.player_name.compareTo(object.player_name);
    }
}

sort

Player p[] = new Player[t];
// do stuff
Arrays.sort(p);

You'd need to have a getter on the number variable for this to work, like:

public class Player {
   public String player_name;
   public int number;

   public int getNumber() {
       return number;
   }
}

Then, as of Java 8, you can sort it by using the Comparing factory class:

Player[] p = new Player[t];
Arrays.sort(p, Comparator.comparingInt(Player::getNumber));

This will:

• Create a Comparator<Person>, by comparing no the getNumber method.
• What you see here is a method reference, which is shorthand for the lambda p -> player.getNumber(), which maps the player to the number.