Undefined offset notice because of array definition in php

Question

I try to define an array, but although having read all of the suggestion here, I still got an error notice when execute.

My form consist among everything else, field min which define the number of textareas in

<input type="text" name="min[1]">

My PHP file has:

<?php
$min = $_POST['min'];
$area = array();

for($j=1; $j=<$length; $j++) {
if($_POST['row'][$j] != "") {

    if(($_POST['min'][$j])!="") {
    for($k=1;$k<=$min[$j];$k++) {
    $area[$j] .= '<textarea name="label'.$j.$k.'" rows="3"' ></textarea>';
    }}
    if(($_POST['min'][$j])=="") {
    $area[$j] = '<textarea name="label'.$j.$k.'" rows="3"'" ></textarea>';
    }
    $blah .= $j.') '.$row[$j].'<br/>'.$area[$j].'<div id="inner'.$j.'"></div><br/><br/>';
}}

I can see that the problem is in array, because the script try to locate the keys which are not there. So how to defne this in advance... This works but it's no solution as you can se:

$area = array("","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","","",);

Your code isn't syntactically valid. It should be clear from coloration of this post itself. — Amal
– Amal, Commented Mar 29, 2014 at 19:04
It is pretty easy. Al of the variables, or actually all of the $_POST methods are called on the simple input text fields. SO, min and row are actually input fields. — mpavlovic89
– mpavlovic89, Commented Mar 29, 2014 at 19:06

John Conde · Accepted Answer · 2014-03-29 19:06:27Z

1

You need to check if that array element exists before you check its value.

Change

if(($_POST['min'][$j])!="") {

to

if(isset($_POST['min'][$j]) && $_POST['min'][$j])!="") {

answered Mar 29, 2014 at 19:06

John Conde

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1 Comment

mpavlovic89 Over a year ago

Actually didn't work in my case. The problem is in array $area. Because it is not defined by $_POST['min']. It should be defined somehow in the loop, but I don't know how

user457015 · Accepted Answer · 2014-03-29 19:28:11Z

0

$length is not initialized...

In PHP the first array index is 0.

You could iterate through array with the foreach operator.

If you copy $_POST['min'] in $min , use it. stop using $_POST['min'] it's confusing.

answered Mar 29, 2014 at 19:28

user457015

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1 Comment

user457015 Over a year ago

@user3244442 There is probably other problems with your code.

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