PHP submit form not working

Question

Below is a piece of the code that input the results of a query into radio buttons. Then, when the user pushes one of the buttons in the form, it moves to the pages test.php. I have run into a problem though that the second code (which is on test.php) doesn't seem to work although I can't see any reason that it shouldn't. Any ideas are awesome. Thanks.

<?php while($row = mysql_fetch_assoc($result)): ?>
<tr>
    <td><input type="radio" name="server" value="<?php echo $row['serverId']; ?>" /></td>
    <td><?php echo $row['userName']; ?></td>
    <td><?php echo $row['dateCreated']; ?></td>
    <td><?php echo $row['serverName']; ?></td>
    <td><?php echo $row['serverId']; ?></td>
    <td><?php echo $row['publicDNS'] ?></td>
    <td><?php echo $row['isRunning']; ?></td>
</tr>
<?php endwhile; ?>
</table>
<br>
<?php endif; ?>

<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="server_stop" value="Stop Server"/>
<input type="submit" name="server_terminate" value="Terminate Server"/>
</form>

</body>
</html>

Second Code:

<?php
if (isset($_POST['server_stop'])) {
    echo "Server Stopped";
}

if (isset($_POST['server_terminate'])) {
    echo "Server Terminated"
}

?>

Companjo · Accepted Answer · 2014-03-31 03:12:15Z

1

$_POST['submit'] has to be $_POST['server_stop']

<?php
if (isset($_POST['server_stop'])) {
    echo "Server Stopped";
}

if (isset($_POST['server_terminate'])) {
    echo "Server Terminated";
}

?>

edited Mar 31, 2014 at 3:12

answered Mar 31, 2014 at 2:54

Companjo

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3 Comments

h3tr1ck Over a year ago

I updated the code, but it still does not display what is inside the echo statements. Any other ideas?

Companjo Over a year ago

I edited the code, try again. I Changed echo "Server Terminated" to echo "Server Terminated";

h3tr1ck Over a year ago

Thank you. Can't believe I missed that semi-colon

Gary Hayes · Accepted Answer · 2014-03-31 03:44:41Z

Your code:

<?php
if (isset($_POST['server_stop'])) {
    echo "Server Stopped";
}

if (isset($_POST['server_terminate'])) {
    echo "Server Terminated"
}

?>

Both of these conditions are true on form submit. If you want to differentiate between which submit button was pressed, you'll need to make a hidden input and use some javascript:

<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="server_stop" value="Stop Server" onclick="whatwasclicked(this);" />
<input type="submit" name="server_terminate" value="Terminate Server" onclick="whatwasclicked(this);" />
<input type="hidden" name="clicked" id="clicked" />
</form>

Your javascript will be:

function whatwasclicked(c) {
$("#clicked").val() = c.value;
}

Now on the PHP side, you'll check $_POST['clicked'] and see which button was pressed.

EDIT: Be aware there is Jquery being used here... so be sure to load that library.

Gary Hayes · Accepted Answer · 2014-03-31 03:51:33Z

0

If you don't want to use javascript at all, and you're only going to have those submit buttons in the form, you could also do this:

<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="clicked" value="Stop Server"/>
</form>
<form method="post" name="server_information" id="server_information" action="test.php">
<input type="submit" name="clicked" value="Terminate Server"/>
</form>

Now just check for $_POST['clicked'] and you'll see which button was pressed.

answered Mar 31, 2014 at 3:51

Gary Hayes

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Comments

e0k · Accepted Answer · 2016-02-20 06:46:01Z

0

if (isset($_POST['submit'])){
  $name =trim($_POST['name']);
  if (empty($name)){
    echo "please input name";    
  }
  else if (!preg_match("/^[a-zA-Z ]*$/",$name)){
    $namerr = "Only letters and white space allowed";
  }
}

edited Feb 20, 2016 at 6:46

e0k

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answered Feb 20, 2016 at 6:10

Ashok K. Kumawat

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1 Comment

Ashok K. Kumawat Over a year ago

elseif (!preg_match("/^[a-zA-Z ]*$/",$name)) { $namerr = "Only letters and white space allowed"; }

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