Show integer as binary sequence (java) [duplicate]

Question

Say I have an integer number: 11728322732 how can i convert it to a string according to its byte representation, i.e 11100011000000001100000111110001 (32 bits \ 4 bytes \ integer)

Thanks

xav · Accepted Answer · 2014-04-03 22:40:47Z

0

Here it is:

Long.toBinaryString(11728322732L);

Actually, 11728322732 is not an Integer but a Long (because it is greater than Integer.MAX_VALUE). So if you really want to convert this long to a 32-bits int (can't figure why actually), you could do:

Integer.toBinaryString((int)11728322732L);

edited Apr 3, 2014 at 22:40

answered Apr 3, 2014 at 22:32

xav

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5 Comments

aliteralmind Over a year ago

Good answer, but that number is bigger than Integer.MAX_VALUE ;)

xav Over a year ago

@aliteralmind good one. Fixed it!

TomM12 Over a year ago

I use integers so Integer.toBinaryString(...) works just fine, thanks

TomM12 Over a year ago

Does anyone knows how can I convert a binary representation back to int ? for instance 11000000 to 192 ?

xav Over a year ago

Integer.parseInt("11000000", 2); (that means "convert it from base 2")

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