For loop a pointer char in c

Question

I have a code that is supposed to get the time , I want to store the time in my char array but I cannot do that so , I thought that I could have a loop to a pointer and loop through the pointer and copy the chars from the pointer memory to my char, is that possible?

void My_Time(char *myt_Time,int size) 
{
    time_t raw_Time = time(0);
    struct tm *info;
    char *myt_Temp;
    int x;

        info = localtime(&raw_Time);
        myt_Temp = asctime(info);
        for (x=0;x<size;x++)
        {
          myt_Time[x]=myt_Temp;
        }
}

You need to stop when you reach the trailing NULL in myt_Temp. You can use strncpy to do this, instead of writing your own loop. — Barmar
– Barmar, Commented Apr 4, 2014 at 16:34

Taiki · Accepted Answer · 2014-04-04 16:34:11Z

2

From what I understand of your problem, the following code should work, instead of your for loop.

strncpy(myt_Time, mytTemp, size);

The bug in your for loop is there:

myt_Time[x]=myt_Temp; => myt_Time[x]=myt_Temp[x];

answered Apr 4, 2014 at 16:34

Taiki

6395 silver badges13 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Barmar Over a year ago

SIZE_OF_MYT_TIME should just be size.

Collectives™ on Stack Overflow

For loop a pointer char in c

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related