Method Overloading for Primitive and Object types

Question

public class OverloadTest {

    public static void main(String ar[]){
         OverloadTest t = new OverloadTest();
         t.add(5,5);
    }

    // 1st method
    public void add(int i , int j){
         System.out.println("In Primitive type" + (i+j))
    }

    // 2nd method
    public void add(Integer i , Integer j){
         System.out.println("In Object type" + (i+j))
    }

}

This code works perfectly. I want to understand should not there a compile time error as 5 will be autoboxed to an Integer Object (Integer.valueOf(5)) and should choose 2nd Method. Why there is no compile time error ?

Why do you think it should be boxed to Integer?

Sotirios Delimanolis
– Sotirios Delimanolis

2014-04-07 14:41:43 +00:00
Commented Apr 7, 2014 at 14:41 — Sotirios Delimanolis
– Sotirios Delimanolis, Commented Apr 7, 2014 at 14:41

arshajii · Accepted Answer · 2014-04-07 14:42:49Z

3

Why would you expect there to be autoboxing? When searching for an appropriate method, the compiler first checks to see if there are applicable methods for the plain int types. Only if such a method is not found does autoboxing come into play.

This process is described in the JLS §18.5.1.

answered Apr 7, 2014 at 14:42

arshajii

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