int[] myArray = new int[] {1,2,3,4,5,6,7,8,9,10};
for(int number : myArray) {
System.out.println(myArray[number]);
}
and this is the output:
2
3
4
5
6
7
8
9
10
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
at javaPractice.selfAssignArrays.main(selfAssignArrays.java:10)
what's wrong with it?
You want to do this:
for (int number : myArray) {
System.out.println(number);
}
This is equivalent to this:
for (int i=0; i<myArray.length; i++) {
int number = myArray[i];
System.out.println(number);
}
Because the enhanced for loop sets number to each value in myArray, not to each index. (Note that the first element being printed is 2, which is the element at index 1.) Your enhanced for loop is more or less equivalent to:
for (int i = 0; i < myArray.length; i++) {
int number = myArray[i];
System.out.println(myArray[number]);
}
What you want is:
for (int number : myArray) {
System.out.println(number);
}
For each iteration, you get the number from array, and you take the number as the index. that's why ArrayIndexOutOfBoundsException happened.
System.out.println(myArray[1]); System.out.println(myArray[2]); System.out.println(myArray[3]); System.out.println(myArray[4]); System.out.println(myArray[5]); System.out.println(myArray[6]); System.out.println(myArray[7]); System.out.println(myArray[8]); System.out.println(myArray[9]); System.out.println(myArray[10]);
Get it?
You should start from System.out.println(myArray[0]); and end at System.out.println(myArray[9]);
Alternatively, just output the number as System.out.println(number);
myArray[number]do? What is each value ofnumberat each iteration? What is the base index of an array?