How to call each method in some array with jQuery

Question

I have this code

var fields = [
    'ile_sprzedal', 'ile_zarobil', 'srednia_kwota', 'konwersja', 'punkty'
];
fields.each(function(i, v){
    var sum = sum_ + v;
        sum = 0;
    var it = it_ + v;
        it = 0;
});

and this error: TypeError: Object [object Array] has no method 'each'. And the question is - How to call each method on some array?

what is the purpose of sum and it as you are resetting it as soon after calculating it — Arun P Johny
– Arun P Johny, Commented Apr 8, 2014 at 14:17
Yes, forEach is the right one; You still can take a look at stackoverflow.com/questions/9329446/… — Regent
– Regent, Commented Apr 8, 2014 at 14:18
if it's jquery, it would be $.each(fields, function(i, v) {... — adeneo
– adeneo, Commented Apr 8, 2014 at 14:20

Arun P Johny · Accepted Answer · 2014-04-08 14:18:31Z

3

Array does not have a each() method, it has forEach() like - Supported by IE>=9

var fields = [
    'ile_sprzedal', 'ile_zarobil', 'srednia_kwota', 'konwersja', 'punkty'];
fields.forEach(function (v, i) {
    var sum = sum_ + v;
    sum = 0;
    var it = it_ + v;
    it = 0;
});

Or jQuery has a $.each() method - cross browser

var fields = [
    'ile_sprzedal', 'ile_zarobil', 'srednia_kwota', 'konwersja', 'punkty'];
$.each(fields, function (i, v) {
    var sum = sum_ + v;
    sum = 0;
    var it = it_ + v;
    it = 0;
});

answered Apr 8, 2014 at 14:18

Arun P Johny

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Comments

Igor · Accepted Answer · 2014-04-08 14:19:10Z

0

Well fields is just a plain array. The $().each() (https://api.jquery.com/each/) call is restricted for jQuery objects. So you need to either wrap fields in a jQuery object ($(fields).each) or just use the $.each call: $.each(fields, function(i, v) (https://api.jquery.com/jQuery.each/).

answered Apr 8, 2014 at 14:19

Igor

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Comments

Alberto De Caro · Accepted Answer · 2014-04-08 15:54:00Z

0

If you are using jQuery:

$.each(fields, function(index, item){
    /* further processing */
});

edited Apr 8, 2014 at 15:54

answered Apr 8, 2014 at 14:18

Alberto De Caro

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1 Comment

Useless Code Over a year ago

As @A.Wolff points out, you shouldn't use $(selector).each() for this; instead $.each() should be used if you are iterating over an array or object. They have similar names and can easily be confused, but they are not the same.

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