Nesting HTML/PHP statement inside another PHP statement

Question

I have an IF/ELSE statement and I would like to print out some images that I am getting from my Drupal site. I can't figure out how to print those IMG tags without getting errors.

This is what I have so far:

<?php
   $field = field_get_items('node', $node, 'field_visitor_image');
 if($field){

        <img src="<?php print image_style_url('lead_teaser', $node->field_visitor_image['und'][0]['uri']); ?>">

            }
        else        
        { 

   <img src="<?php print image_style_url('lead_teaser', $node->field_banner_image['und'][0]['uri']); ?>">

        }        
?>

I just love the peanut gallery around here. I am learning. So sue me if I don't act like a "real coder". — Dan
– Dan, Commented Apr 9, 2014 at 22:11
What's the difference between what you're printing in the if and the else? They look the same to me. — Barmar
– Barmar, Commented Apr 9, 2014 at 22:12

Quentin · Accepted Answer · 2014-04-09 22:09:48Z

5

You have to break out of PHP mode when you start outputting HTML.

if($field){
?>
    <img src="<?php print image_style_url('lead_teaser', $node->field_visitor_image['und'][0]['uri']); ?>">
<?php
}

answered Apr 9, 2014 at 22:09

Quentin

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Comments

Barmar · Accepted Answer · 2014-04-09 22:11:21Z

3

Use echo and string concatenation:

if ($field) {
    echo '<img src="' . image_style_url('lead_teaser', $node->field_visitor_image['und'][0]['uri']) . '">';
}

answered Apr 9, 2014 at 22:11

Barmar

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1 Comment

Dan Over a year ago

Thanks Barmar. That worked wonderfully. I appreciate you help!

user5571127 · Accepted Answer · 2017-05-20 15:31:45Z

0

You cannot nest

<?php > inside another  <?php >.

One option for you could be to concatenate using ".".

answered May 20, 2017 at 15:31

user5571127

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