String Array for Java

Question

I have a question regarding making String arrays in Java. I want to create a String array that will store a specific word in each compartment of the string array. For example, if my program scanned What is your deal? I want the word What and your to be in the array so I can display it later.

How can I code this? Also, how do I display it with System.out.println();?

Okey so, here is my code so far:

import java.util.Scanner;
import java.util.StringTokenizer;

public class OddSentence {

    public static void main(String[] args) {

        String sentence, word, oddWord;
        StringTokenizer st;

        Scanner scan = new Scanner (System.in);


        System.out.println("Enter sentence: ");
        sentence = scan.nextLine();

        sentence = sentence.substring(0, sentence.length()-1);
        st = new StringTokenizer(sentence);

        word = st.nextToken();


        while(st.hasMoreTokens()) {
            word = st.nextToken();
            if(word.length() % 2 != 0) 

        }

        System.out.println();
    }
}

I wanted my program to count each word in a sentence. If the word has odd numbers of letter, it will be displayed.

What have you tried to do so far? Have you looked through the available methods in the String class itself? — JonK
– JonK, Commented Apr 9, 2014 at 22:33
What criteria are you using to determine what words should be in the array? As in, why are only What and your contained in the array? — Whymarrh
– Whymarrh, Commented Apr 9, 2014 at 22:33
If you use next instead of nextLine, the Scanner will do your tokenisation and you can just grab your input in a loop. Then you don't need either split or your StringTokenizer. — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Apr 9, 2014 at 22:51
@DavidWallace How would I implement it in a loop if i change the nextLine to next and would it display all the words? — m.lacabe
– m.lacabe, Commented Apr 9, 2014 at 22:56
while(scan.hasNext()) { word = scan.next(); if(word.length() % 2 != 0) { // do stuff } } — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Apr 9, 2014 at 23:01

Rogue · Accepted Answer · 2014-04-09 22:33:48Z

2

Based on what you've given alone, I would say use #split()

String example = "What is your deal?"
String[] spl = example.split(" ");
/*
  args[0] = What
  args[1] = is
  args[2] = your
  args[3] = deal?
*/

To display the array as a whole, use Arrays.toString(Array);

System.out.println(Arrays.toString(spl));

answered Apr 9, 2014 at 22:33

Rogue

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5 Comments

Paul Richter Over a year ago

Arrays#toString would be a better method of displaying the array in this way.

m.lacabe Over a year ago

Actually, I have a Scanner so that when the program is ran, it will ask the user to enter a sentence and what ever the sentence is, I will use a StringTokenizer to go through each word in a sentence.

Dawood ibn Kareem Over a year ago

From the Javadoc for StringTokenizer - "StringTokenizer is a legacy class that is retained for compatibility reasons although its use is discouraged in new code. It is recommended that anyone seeking this functionality use the split method of String or the java.util.regex package instead."

Rogue Over a year ago

@PaulRichter That is what I have in my answer (I did say list originally, but changed it within the first minute).

Paul Richter Over a year ago

@Rogue Ah yes, I see that now. I'm on my phone; sadly it doesn't auto publish changes until I refresh the screen.

Rogue · Accepted Answer · 2014-04-09 22:35:52Z

1

To read and split use String.split()

final String input = "What is your deal?";
final String[] words = input.split(" ");

To print them to e.g. command line, use a loop:

for (String s : words) {
    System.out.println(s);
}

or when working with Java 8 use a Stream:

Stream.of(words).forEach(System.out::println);

edited Apr 9, 2014 at 22:35

Rogue

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answered Apr 9, 2014 at 22:34

ifloop

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Comments

DerStrom8 · Accepted Answer · 2014-04-10 10:47:02Z

0

I agree with what the others have said, you should use String.split(), which separates all elements on the provided character and stores each element in the array.

String str = "This is a string";
String[] strArray = str.split(" ");   //splits at all instances of the space & stores in array
for (int i = 0; i < strArray.length(); i++) {
  if((strArray[i].length() % 2) == 0) {  //if there is an even number of characters in the string
    System.out.println(strArray[i]);     //print the string
  }
}

Output:

This is string

If you want to print the string when it has an odd number of characters, simply change if((strArray[i].length() % 2) == 0) to if((strArray[i].length() % 2) != 0)

This will give you just a as the output (the only word in the string with an odd number of characters).

edited Apr 10, 2014 at 10:47

answered Apr 10, 2014 at 0:09

DerStrom8

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1 Comment

RRM Over a year ago

Instead of using the for loop, we could utilize Arrays.deepToString(Object[] args);

rafalio · Accepted Answer · 2014-04-09 22:33:47Z

0

Let input be your input string. Then:

String[] words = input.split(" ");

answered Apr 9, 2014 at 22:33

rafalio

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