Finding even numbers using a recursive method

Question

I am trying to have the code listed below receive an int input from user, then find amount of even numbers in that int. I'm getting an error when I try to print the return... any help?

import java.util.Scanner;
public class evenDigits {

public static int countEvenDigits(int number){
    if (number == 0)
        return 0;
    else{
        int lastDigit = number % 10;
        int result = countEvenDigits(number / 10);
        if (lastDigit % 2 == 0)
            return result + 1;
        else
            return result;
    }
}

public static void main(String[] args) {

    System.out.println("Please enter an integer.");
    Scanner keyboard = new Scanner(System.in);
    int number = keyboard.nextInt();

    countEvenDigits(number);

    System.out.println("There are " + result + " even digits in " + number);


}

}

Specifically, there is an error in this statement:

System.out.println("There are " + result + " even digits in " + number);

Specifically, there is an error in this statement: System.out.println("There are " + result + " even digits in " + number); — user3503240
– user3503240, Commented Apr 11, 2014 at 1:43
You're not receiving the return value from countEvenDigits in main! You haven't even defined result in main. — ooga
– ooga, Commented Apr 11, 2014 at 1:44
Try int result = countEvenDigits(number); in your main. result is only declared in the method, not in your main. — Sebastian Höffner
– Sebastian Höffner, Commented Apr 11, 2014 at 1:47

Barmar · Accepted Answer · 2014-04-11 01:46:40Z

2

In main you need to change:

countEvenDigits(number);

to:

int result = countEvenDigits(number);

Otherwise, you're accessing a nonexistent variable in your println

answered Apr 11, 2014 at 1:46

Barmar

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