So I've just figured out that you can use string->number to convert string 365 into int 365. But now I have another question:
How do I take, for example, (1 2 3), and convert it to string 123 so I can apply string->number to it? Any help would be appreciated. Thanks!
If it helps: I am using drracket 6.0
I'm going to answer your original question, not your current one, which is just one possible solution approach.
There are a number of ways to solve this. One way, like you mentioned in this question, is to convert the incoming list of numbers into strings, then concatenating them:
(require srfi/13)
(define (number-concatenate nums)
(string->number (string-concatenate (map number->string nums))))
Here's another approach, that does not involve conversion to strings first:
(require srfi/1 srfi/26)
(define (number-concatenate nums)
(define (expand num)
(if (< num 10)
(list num)
(unfold-right zero? (cut modulo <> 10) (cut quotient <> 10) num)))
(fold (lambda (num result)
(fold (lambda (digit result)
(+ digit (* result 10)))
result (expand num)))
0 nums))
If you have array of numbers you can do like this(javascript code)-
[1,2,3].join('');
o/p=>"123"
'(123 45 6)into the number 123456.)