search a file using python

Question

my problem is when I search a pdf file using python. I search it line by line so suppose I have a line contains:

"this this this %this"

so if we put x = "this this this %this" and I want to count the number of "this" and ignore what proceeds "%" as it is a comment. the code is :

if re.search("%",x):
    new_line = x.split()
    for g in new_line:
        if re.search("%",g):
            break
        elif g == "this":
            counter = counter+1
    print (counter)

but what if I have the following:

x = "this this this %this %this" the second percentage ends the comment and I want to skip "this" which is between "%" and count the last one

have any one any Idea to do it ?

If you are opening a PDF file as a text file and attempting to parse out the contents, be aware that PDF files often do not store their contents in sequential text strings as it appears on the output. Parsing raw PDF can be an essentially impossible task. — Larry Lustig
– Larry Lustig, Commented Apr 11, 2014 at 16:11

Khaelex · Accepted Answer · 2014-04-11 16:14:48Z

1

You could try

x = re.sub("%[^%]*%?", "", x);

Demo: http://regex101.com/r/tE6rL7

edited Apr 11, 2014 at 16:14

answered Apr 11, 2014 at 16:04

Khaelex

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1 Comment

user3461464 Over a year ago

Than you very much it worked like a magic. please I'm working in a project and I need further help if you don't mind?

Hugh Bothwell · Accepted Answer · 2014-04-11 16:03:44Z

0

data = "this this this %this %this"

data = ' '.join(data.split('%')[::2])

data # => "this this this  this"

answered Apr 11, 2014 at 16:03

Hugh Bothwell

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1 Comment

user3461464 Over a year ago

thank you very much. could I ask you more question if you don't mind?

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