While count in python

Question

user_answer = (raw_input('Can you guess the word that is missing? ')).lower()
count =0
while count <=1:
     if user_answer == 'brown':
          print ('Well done')
          break
     else:
          user_answer =(raw_input('Please Guess again? '))
          count+=1
else:
     print ("Fail Game")

I'm working on a simple game and it allows the user to input the wrong guess three times. I have been playing around with this while loop and it works, (while count <=1) but i am a little confused as too why??? (not complaining) but can anyone explain why it works as i originally though the code should be like to one below (but these uses 5 attempts)

count = 0
while count <=3:

all rest of code is same as above.

Christian Tapia · Accepted Answer · 2014-04-13 19:01:12Z

2

The maximum number of inputs you can get with that code is 3. Why?

The first is outside the loop.
The second is when count is 0. After the input, count will be 1.
The third (and last) is when count is 1. After the input, count will be 2. The loop will finish in the next iteration because the condition 2 <= 1 will be False.

answered Apr 13, 2014 at 19:01

Christian Tapia

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1 Comment

P_Lee Over a year ago

i didn't think about the 1st instance of the first one outside the loop. Makes sense now.

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