I believe this is a long shot, but consider the following:
public function options(array $options = ['route' => '', 'placeholder' => '']) {}
Could I invoke this method such as:
options(['route' => 'search'])
And maintain placeholder as 'placeholder' => ''
Is there anything that could merge the original $options array with the new one?
You could maintain an array of default options and then merge them with the supplied function parameters.
function options(array $options = [])
{
$defaults = ['route' => '', 'placeholder' => ''];
$options = array_merge($defaults, $options);
// ...
}
options(['route' => 'search']);
Now, all the following would work:
options(['route' => 'search']);
options(['route' => 'search', 'placeholder' => 1]);
options();
Output:
array(2) {
["route"]=>
string(6) "search"
["placeholder"]=>
string(0) ""
}
array(2) {
["route"]=>
string(6) "search"
["placeholder"]=>
int(1)
}
array(2) {
["route"]=>
string(0) ""
["placeholder"]=>
string(0) ""
}
The answer by Amal Murali is also correct, but, in the place of array_merge() one should consider using array_merge_recursive() so that default options are not overwritten by the options passed when calling the function.
For example:
function getQuiz(array $options) {
$default = array(
'conditions' => array(
'deleted' => 0
)
);
$options = array_merge_recursive(
$default,
$options
);
print_r($options);
}
and then calling it like:
$options = array(
'conditions' => array(
'id'=>1
)
);
getQuiz( $options );
Doing a print_r( $options ) inside getQuiz() would give:
array(
conditions' => array(
'id' => '3',
'deleted' => 1
)
)
