Java remove whitespace on string

Question

I crawl a site and i get some prices from it. I get a price with its currency (21,00 TL) i should remove currency(TL) and the left whitespace on it for convert double to string. In short i should get 21.00 . Whatevery i did , i couldnt remove that whitespace.

I got from crawler :

<b>21,00&nbsp;TL</b>

What i try:

price_lower_str = price_lower_str.replace("&nbsp;TL","");

and 

price_lower_str = price_lower_str.replace(" TL","");

price_lower_str = price_lower_str.replace("TL","");
price_lower_str = price_lower_trim();

but i couldnt get only 21.00 . Who can help me?

Thanks

How about trim() ? price.trim() will remove last whitespace. — arghtype
– arghtype, Commented Apr 17, 2014 at 13:19

Harmlezz · Accepted Answer · 2014-04-17 13:27:08Z

1

Quick and dirty, but working :-)

public static void main(String[] args) {
    String str = "<b>21,00&nbsp;TL</b>";
    Matcher matcher = Pattern.compile(".*?([\\d]+,[\\d]+).*").matcher(str);
    if (matcher.matches()) System.out.println(matcher.group(1).replace(',', '.'));
}

OUTPUT:

21.00

edited Apr 17, 2014 at 13:27

answered Apr 17, 2014 at 13:20

Harmlezz

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8 Comments

FrobberOfBits Over a year ago

This fails to remove   specified by OP's input.

Harmlezz Over a year ago

It does not fail, because it matches only digits, the comma and digits. Never the less, it is ugly. It is easy for you to proof it right?

Mike Tunnicliffe Over a year ago

I think there was a glitch in your code, probably a copy-paste error. Otherwise, it seems to give the proper requested output.

Mike Tunnicliffe Over a year ago

That's better :) Glitch fixed.

FrobberOfBits Over a year ago

Except the question was how to remove the whitespace, not how to extract the digits. OP hasn't specified that those digits and commas are the only valid values in those cells. What happens when the next input value is BLAHBLAH&ampnbsp;TL

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FrobberOfBits · Accepted Answer · 2014-04-17 13:21:23Z

1

You're just using the wrong regular expression. Try this:

price_lower_str.replaceAll("(\\&nbsp;|\\s)+TL", "")

First, I'm using replaceAll and not just replace as you are. Second, notice the parens - I'm replacing EITHER   OR \s which matches any whitespace character. Finally, I'm escaping via backslashes the ampersand in   Escaping backslashes when backslash itself is a meta-character in regex is a pain, but welcome to java regex.

answered Apr 17, 2014 at 13:21

FrobberOfBits

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1 Comment

FrobberOfBits Over a year ago

I tested this on your input string 21,00 TL and it does work. You need to provide which input you're using that it doesn't work on. What do you have, and what do you expect?

Yann Laviolette · Accepted Answer · 2014-04-17 13:50:27Z

1

Using regexes sound to heavy for this simple processing. It's not really efficient in that case. What you could do is to locate the > from the < b > tag and do a substring up to the amperstand.

System.out.println(test.substring(test.indexOf(">")+1, test.indexOf("&")));

You will get your answer 21,00

answered Apr 17, 2014 at 13:50

Yann Laviolette

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