Python Convert Int List to Decimal string then back to Int List

Question

I need to pass a list of numbers in a 3D program I'm using but it can only pass a single value. I want to pass the list as a single string separated by decimal points and then later convert that string back to a list. Here's the outcome I'm looking for:

a=[8,9,10,11] # will always contain integers

list elements converted to decimal then join as a string

a=".8.9.10.11"

then later on convert that string back to a list

a=[8,9,10,11]

I'm thinking it's a combo of the map() and join() function but I'm not exactly sure. Thanks for any help!

Might want to just keep the original list instead of converting and reconverting. — C.B.
– C.B., Commented Apr 17, 2014 at 15:12

anon582847382 · Accepted Answer · 2014-04-17 15:43:37Z

4

Starting with a as [8,9,10,11]:

First one would be (to string):

a = ''.join('.{0}'.format(d) for d in a)
# ".8.9.10.11"

Second would be (back to list of ints again):

a = [int(i) for i in a.split('.')[1:]]
# [8, 9, 10, 11]

edited Apr 17, 2014 at 15:43

answered Apr 17, 2014 at 15:12

anon582847382

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3 Comments

Motion4D Over a year ago

@AlexThornton Thanks for the lighting fast reply. I'm sure this works but im getting a "zero length field name in format" error. This software runs on python 2.6 I believe, would that have anything to do with it?

anon582847382 Over a year ago

Ah, I see. It's easy to fix, see the edit. Notice the 0. :)

anon582847382 Over a year ago

@Motion4D You're very welcome, come back any time. :)

anon582847382 · Accepted Answer · 2014-11-01 15:21:52Z

3

To convert that list to a string, just do:

a=[8,9,10,11]
b = '.'+'.'.join(a)

>>> print b
.8.9.10.11

To get the list back from the string, you do:

b = '.8.9.10.11'
a = b[1:].split('.')

>>> print a
[8,9,10,11]

edited Nov 1, 2014 at 15:21

anon582847382

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answered Apr 17, 2014 at 15:10

sshashank124

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Comments

mblw · Accepted Answer · 2014-04-17 15:14:37Z

0

a = [8, 9, 10, 11]
b = '.' + '.'.join(str(x) for x in a)
v = [int(x) for x in b.split('.')[1:]]

answered Apr 17, 2014 at 15:14

mblw

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