Regex to find specific number using Python regex

Question

I need a regex to find the maxtimeout value (40 in the following) in the RequestReadTimeout directive in Apache config. file, for example :

RequestReadTimeout header=XXX-40,MinRate=XXX body=XXX
RequestReadTimeout header=40 body=XXX

PS : XXX refer to a decimal digit

I used this :

str="RequestReadTimeout header=10-40,MinRate=10 body=10"
re.search(r'header=\d+[-\d+]*', str).group()
'header=10-40'

But I need a regex to get only the maxtimeout value (40 in this example) in one row (without using other function like spit("-")[1] ...etc).

Thanks.

Martijn Pieters · Accepted Answer · 2014-04-18 10:13:31Z

2

You'd group the part you wanted to extract:

re.search(r'header=(?:\d*-)?(\d+)', inputstr).group(1)

The (...) marks a group, and positional groups like that are numbered starting at 1.

I altered your expression a little to only capture the number after an optional non-capturing group containing digits and a dash, to match both patterns you are looking for. The (?:...) is a non-capturing group; it doesn't store the matched text in a group, but does let you use the ? quantifier on the group to mark it optional.

Pythex demo.

Python session:

>>> import re
>>> for inputstr in ('RequestReadTimeout header=1234-40,MinRate=XXX body=XXX', 'RequestReadTimeout header=40 body=XXX'):
...     print re.search(r'header=(?:\d*-)?(\d+)', inputstr).group(1)
... 
40
40

edited Apr 18, 2014 at 10:13

answered Apr 18, 2014 at 10:08

Martijn Pieters

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Comments

sshashank124 · Accepted Answer · 2014-04-18 10:13:54Z

0

You could do it with the following regex:

'RequestReadTimeout\sheader=(?:\d+)?-?(\d+).*'

The first captured group \1 is what you want

Demo: http://regex101.com/r/cD6hY0

edited Apr 18, 2014 at 10:13

answered Apr 18, 2014 at 10:07

sshashank124

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1 Comment

TMR_OS Over a year ago

Works for your nice solution !

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