How to parse this URL in java

Question

I have a URL like this

http://my.my.info/action/doning/something?mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=

I need it in key value pair not as a query string.

my out put should be

mailParams = iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=

i could not parse this string since the above is encoded. I have used URLEncodedUtils to parse this but it returns

mailParams = iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ vx43P4g umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW KjUi3JubtJT 0F7p wPHEpTRwJJ O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA

which is not at all relevant can some one help me to do this?

I know that the plus is translated i need how to fetch that parameter from that string.. — ashokramcse
– ashokramcse, Commented Apr 21, 2014 at 6:27
Make up your mind. Either you want the + or you want it decoded, correctly, to a space. And if you want the +, why? It wasn't sent that way, and if it was it shouldn't have been: don't compensate for a bug by adding another one. — user207421
– user207421, Commented Apr 21, 2014 at 6:47

user3547829 · Accepted Answer · 2014-04-21 06:29:23Z

3

Try using java.net.URL

A sample code below.

    URL aURL = new URL("http://my.my.info/action/doning/something?mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=");

    System.out.println("protocol = " + aURL.getProtocol());
    System.out.println("authority = " + aURL.getAuthority());
    System.out.println("host = " + aURL.getHost());
    System.out.println("port = " + aURL.getPort());
    System.out.println("path = " + aURL.getPath());
    System.out.println("query = " + aURL.getQuery());
    System.out.println("filename = " + aURL.getFile());
    System.out.println("ref = " + aURL.getRef());

answered Apr 21, 2014 at 6:29

user3547829

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Community · Accepted Answer · 2017-05-23 12:22:17Z

1

If need to split the link to get the parameters

use String#split which takes the regex as a arguments

String link="http://my.my.info/action/doning/something?mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=";
        String[] mailparams=link.split("\\?");
        System.out.print(mailparams[1]);

You can also Use URL#getQuery

String link="http://my.my.info/action/doning/something?mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=";
         URL aURL = new URL(link);
        System.out.println( aURL.getQuery());

OUTPUT:

mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=

edited May 23, 2017 at 12:22

CommunityBot

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answered Apr 21, 2014 at 6:30

Nambi

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2 Comments

Nambi Over a year ago

@ashokramcse it will returns your excepted output isn't ?

ashokramcse Over a year ago

K what happens when i split your query using =

Niraj Patel · Accepted Answer · 2014-04-21 06:42:30Z

0

URL aURL = null;
try {
    aURL = new URL("http://my.my.info/action/doning/something?mailParams=iCgGugAIdMW3CqkYbZ/dGYVqljerVjzbKLvTQCyuosHzxisIrgYf8rcKqRhtn90Z0eVGZ+vx43P4g+umFmddNdDufWv/nDwbCgqBwHs9OYVd5g4VKuFO4jTfF1NiW+KjUi3JubtJT+0F7p+wPHEpTRwJJ+O0eevojx6DioK3cLGejz5UdfIrqzOVNT05TaPKFie4yZxbXfA=");
} catch (MalformedURLException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

System.out.println(aURL.getQuery());

answered Apr 21, 2014 at 6:42

Niraj Patel

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