How do you implement a random number into python

Question

so i am making a basic game in python (on a raspberry pi) and for a x coordinate i need it to be random and it wont work when i use random.randint() and therefore i dont know what to do:

as said i need x to be a random number and y to stay as -2

def getNewPiece():
    shape = random.choice(list(PIECES.keys()))
    newPiece = {'shape': shape,
                'rotation': random.randint(0, len(PIECES[shape]) - 1),
                'x': random.randint(),
                'y': -2 , 
                'color': random.randint(0, len(COLORS)-1)}
    return newPiece

random.randint() always takes 2 arguments; what is the range of values that are allowed for x? Just like rotation and color, the number of values that are legal for x is not limitless. — Martijn Pieters
– Martijn Pieters, Commented Apr 21, 2014 at 9:59

sshashank124 · Accepted Answer · 2014-04-21 09:59:15Z

2

You actually need to pass in your range from which the random int needs to be generated.

random.randint(1,10)

where 1 and 10 are included in the random picking. Therefore, the method above will return any integer between 1 & 10 (inclusive). For a different range, just specify different start and end parameters.

Documentation: random.randint

answered Apr 21, 2014 at 9:59

sshashank124

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Nishant Nawarkhede · Accepted Answer · 2014-04-21 10:14:19Z

0

You can also use randrange ,

Syntax is random.randrange([start], stop[, step])

Example ,

>>> from random import randrange
>>> print randrange(10)
5

edited Apr 21, 2014 at 10:14

answered Apr 21, 2014 at 10:07

Nishant Nawarkhede

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