PHP convert preg_replace to preg_replace_callback

Question

Just wondering how I can convert the following preg_replace() to preg_replace_callback() - I am having difficulty converting to preg_replace_callback() as preg_replace() is been deprecated.

$tableData['query'] = preg_replace('/{%(\S+)%}/e', '$\\1', $tableData['query']);

Replace all $string with $string variable.

Thanks heaps in advance

From the docs - "An E_DEPRECATED level error is emitted when passing in the "\e" modifier." The function itself is not deprecated. — Darragh Enright
– Darragh Enright, Commented Apr 23, 2014 at 11:39
possible duplicate of alternative for function preg_replace e/ modifier — Darragh Enright
– Darragh Enright, Commented Apr 23, 2014 at 11:40
@Darragh Thanks, so do i just remove it or replace with? Sorry pretty bad at regular expression. — Bill
– Bill, Commented Apr 23, 2014 at 22:44

jonnu · Accepted Answer · 2014-04-23 11:52:45Z

1

You can do it this way. I am assuming you know the dangers of eval, so use this at your own risk.

$locals = get_defined_vars();

$tableData['query'] = preg_replace_callback('/{%(\S+)%}/', function ($match) use ($locals) {
    if (!array_key_exists($match[1], $locals)) {
        // the variable wasn't defined - do your error logic here
        return '';
    }
    return $locals[$match[1]];
}, $tableData['query']);

Additional word of warning - any 'declared' variable is fair game! Nothing to stop me having something like this inside the $tableData['query'] variable:

I am evil and want to see {%super_secret_variable%}!

edited Apr 23, 2014 at 11:52

answered Apr 23, 2014 at 11:47

jonnu

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