how to use javascript Regex to extract id: http://site/page?object_id=2

Question

the url: http://site/page?object_id=2 I want the number (id).

I think Gumbo understands what you want, but how you get it can be different depending on the context. Unless we're on a "need to know" basis, and the context that the js is running in is classified... — jball
– jball, Commented Feb 24, 2010 at 18:56
The point is, if you've got a Location object such as window.location or any of the a element nodes, you can use obj.search to get the query string without having to use dodgy regexes that will fail if the URL is in an unexpected form. You should also consider using a proper query string parser that breaks on both & and the alternative ; and does decodeURIComponent on the name and value, if the URL can be in any form. — bobince
– bobince, Commented Feb 24, 2010 at 19:41

SLaks · Accepted Answer · 2010-02-24 18:59:52Z

3

Try the following:

/\?(?:.*?&)?object_id=(\d+)/.exec(url)[1]

Unlike other answers, this will correctly handle http://site/page?other_object_id=3&object_id=2

edited Feb 24, 2010 at 18:59

answered Feb 24, 2010 at 18:54

SLaks

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Christian C. Salvadó · Accepted Answer · 2010-02-24 19:04:10Z

2

If you have the URL in a string:

var str = "http://site/page?other_object_id=10&object_id=2";
var match = str.match(/[?&]object_id=(\d+)/);

if (match) {
  alert(match[1]); // 2
}

If it's the URL of the current page:

var match = location.search.match(/[?&]object_id=(\d+)/);

if (match) {
  alert(match[1]);
}

edited Feb 24, 2010 at 19:04

answered Feb 24, 2010 at 18:54

Christian C. Salvadó

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1 Comment

SLaks Over a year ago

Unless the path contains an &.

Tatu Ulmanen · Accepted Answer · 2010-02-24 18:52:28Z

2

Try this:

var url = 'http://site/page?object_id=2';
var object_id = url.match(/object_id=(\d+)/)[1];

answered Feb 24, 2010 at 18:52

Tatu Ulmanen

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1 Comment

Nicole Over a year ago

I would just take the $ away, your \d+ should work fine. Also put the + inside the parentheses - (\d+).

Quentin · Accepted Answer · 2010-02-24 18:52:35Z

1

foo.match(/(\d+)/);

answered Feb 24, 2010 at 18:52

Quentin

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