Python Checking the Value of an Element in an Array

Question

In my program, I generate two lists each with 10 integers: one through user input, and one through random selection. Then, using numpy, I convert one of the lists into a 2x5 array, and the other into a 5x2 array and take the outer product to arrive at a 5x5 array like this:

 [[ 1 1 1 1 1]
  [ 1 1 1 1 1]
  [ 1 1 0 1 1]
  [ 1 1 1 1 1]
  [ 1 1 1 1 1]]

I want to ask the user some questions about the array, for example, "What is the value in the center of the resulting array?" (which would be 0 in this case).

How can I have Python check the value of the integer at the center of the array?

possible duplicate of Checking elements in a matrix in python — wflynny
– wflynny, Commented Apr 27, 2014 at 18:02
@pez I like the way you describe your question - it is succinct an clear. Keep on going this way. — Jan Vlcinsky
– Jan Vlcinsky, Commented Apr 27, 2014 at 21:18

Glorfindel · Accepted Answer · 2023-01-12 21:06:11Z

2

If your array is arr, arr[2,2] will return the 3rd value down and 3rd value across (because indexing starts with 0). See the documentation.

edited Jan 12, 2023 at 21:06

Glorfindel

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answered Apr 27, 2014 at 17:53

wflynny

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Bryan · Accepted Answer · 2014-04-27 17:56:14Z

1

Given the you are asking for the center, i am assuming that your array is going to have odd dimensions. if that is the case you could use the following:

print arr[len(arr)/2][len(arr[1])/2]

this divides the number of rows and columbs by 2 which will give you the middle index.

answered Apr 27, 2014 at 17:56

Bryan

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Comments

YXD · Accepted Answer · 2014-04-27 18:14:12Z

1

If your array is a square array with odd dimensions you can do

x.ravel()[x.size/2]

edited Apr 27, 2014 at 18:14

answered Apr 27, 2014 at 17:53

YXD

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