From table to array jquery objects

Question

I am attempting to gather values of custom data attributes using each.

Here's what I have so far JSfiddle

Heres the JQ/JS

var multi = $('.till__tablepanel_table_0_row__ticket');
var myarray = [];

$.each(multi, function (index, item) {
    myarray.push( {name: 'ticket_row_num', value: $(item).data('ticket_row_num')} ); 
    myarray.push( {name: 'itemtitle', value: $(item).data('itemtitle')} );
    myarray.push( {name: 'row_quantity', value: $(item).data('row_quantity')} ); 
    myarray.push( {name: 'rowunitprice', value: $(item).data('rowunitprice')} );  
    myarray.push( {name: 'row_total', value: $(item).data('row_total')} ); 

  //  myarray.push( {name: 'measure_type_is_grams', value: $(item).data('measure_type_is_grams')} ); 

});

alert(myarray);

The issue is I am getting [object, Object] being returned, and I don't know why.

I am terribly unfamiliar with arrays in JS/JQ and I am trying to work this out to not much avail.

You can override its toString method to make it output what you want. — Oriol
– Oriol, Commented Apr 29, 2014 at 0:28

Arun P Johny · Accepted Answer · 2014-04-29 00:28:50Z

1

It is because you have an array of objects, which when converted to string gives the o/p [object, Object].. instead try alert(JSON.stringify(myarray)); - it will give a json representation of the object.

It is happening because the default toString() implementation of an object will return [object Object]

answered Apr 29, 2014 at 0:28

Arun P Johny

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