8

I have a list:

Student_Grades = ['56', '49', '63']

and I want to convert each of the entries to integers so that I can calculate an average.

Here's my code for converting:

for i in Student_Grades:
    Student_Grades = [int(i)]

I keep getting the error 

invalid literal for int() with base 10: '56,'

and I don't know what to do.

Here is my full code on how I got Student_Grades Choose_File = str(input("Please enter the exact name of the file to be read in (including file extention) : "))

with open(Choose_File, "r") as datafile:
    counter = 1
    x = 1
    Student_Grades = []
    Read = datafile.readlines()
    info = Read[counter]
    Split_info = info.split()
    n = len(Split_info)


    while x < n:
        Student_Grades.append(Split_info[x])
        x = x + 2

The textfile has the format 'MECN1234 56, MECN1357 49, MATH1111 63'

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6
  • 3
    Your list does not contain just '56'; there is a comma there too. How did you create Student_Grades? Commented Apr 29, 2014 at 21:27
  • I read in a few lines from a textfile with the format: MECN1234 56, MECN1357 49, MATH1111 63 I then split the lines using .split() and then appended the Student_Grades list with every 2nd entry from the split list (which were the grades). Commented Apr 29, 2014 at 21:31
  • Here's my full code: Choose_File = str(input("Please enter the exact name of the file to be read in (including file extention) : ")) with open(Choose_File, "r") as datafile: counter = 1 x = 1 Student_Grades = [] Read = datafile.readlines() info = Read[counter] Split_info = info.split() n = len(Split_info) while x < n: Student_Grades.append(Split_info[x]) x = x + 2 Commented Apr 29, 2014 at 21:32
  • @user3576929 larger pieces of codes is better to add to your question (if it does not change your question), it is much more readable. Commented Apr 29, 2014 at 21:35
  • How would I deal with that comma? Commented Apr 29, 2014 at 21:45

3 Answers 3

Reset to default
21

Apply int on each item in the list and return it as a list:

>>> StudentGrades = ['56', '49', '63']
>>> res = list(map(int, StudentGrades)) # this call works for Python 2.x as well as for 3.x
>>> print res
[56, 49, 63]

Note about map differences in Python 2 and 3

In Python 2.x map returns directly the list, so you may use

>>> res = map(int, StudentGrades)

but in Python 3.x map returns an iterator, so to get real list, it must be wrapped into list call:

>>> res = list(map(int, StudentGrades))

The later way works well in both version of Python

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3 Comments

This returned <map object at 0x00000000032BD518> and I'm not quite sure what this means. Forgive me, I'm new to programming
@user3576929, you must be using Python 3 and @Jan is using python 2. You can fix this by using list(map(int, StudentGrades))
@askewchan Thanks for your comment, I updated my answer to be Python 2 and 3 compatible
12

You should do this:

for i in range(len(Student_Grades)):
    Student_Grades[i] = int(Student_Grades[i])
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2 Comments

I think she wants to update the list.
@BenjaminBannier Yes, I changed it.
8 
In [7]:

Student_Grades = ['56', '49', '63']
new_list = [int(i) for i in Student_Grades]
print(new_list)
[56, 49, 63]
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