Upload multiple files using Python Selenium WebDriver

Question

I have a html element

<input type=file multiple="">

How can I use send_keys to upload multiple files?

Currently this works with uploading single file. I want to use this to upload multiple files

I tried Comma separated paths but no luck.

Separate with '\n', not with comma.

Andrew Anderson
– Andrew Anderson

2022-05-31 16:55:05 +00:00
Commented May 31, 2022 at 16:55 — Andrew Anderson
– Andrew Anderson, Commented May 31, 2022 at 16:55

Prerna Gaikwad · Accepted Answer · 2019-05-31 09:25:23Z

3

path = “/home/downloads/” send_keys(path + “file1.csv \n” + path + “file2.csv”)

I found it working in my code. Do try this and give me update on the error you got.

answered May 31, 2019 at 9:25

Prerna Gaikwad

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Comments

Alpha · Accepted Answer · 2014-04-30 05:36:33Z

1

First, send all files to the element and then submit.

Following is Ruby code, but you can apply same logic for Python:

uploader = driver.find_element(id: 'file-upload')
uploader.send_keys 'path_to_file1'
uploader.send_keys 'path_to_file2'
uploader.send_keys 'path_to_file3'
.
.
.
uploader.submit

I'm not sure if this will work, but just give a try and let me know the result.

answered Apr 30, 2014 at 5:36

Alpha

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Comments

sudo · Accepted Answer · 2017-05-31 19:23:24Z

1

Here is an example that works in my specific case for uploading multiple photos, may help someone out...

Photos is an array of strings i.e. ['/Users/foo/bar/beautiful_forest-1546653.jpg', '/Users/foo/bar/DTHalloween.jpg'] then I loop through and upload them by send_keys. I ensure they are uploaded by checking to see if the uploaded filename exists in the DOM, which it will if successfull (specific to my case). FWIW, I'm testing a react.js web app btw.

def uploadPhoto(self, photos):
    try:
        drop_zone = self.driver.find_element_by_id('photo-file-input')

        alreadyUploaded = []  # keep track of uploaded files

        for photo in photos:
            photo_name = photo.split('/')[-1].split('.')[0]

            if photo_name.lower() in alreadyUploaded:
              print("Photo already uploaded with name: ( "+ photo_name.lower()+" )")
              continue

            alreadyUploaded.append(photo_name.lower())

            drop_zone.send_keys(photo)

            try:
                WebDriverWait(self.driver, 5).until(
                    EC.presence_of_element_located((By.XPATH, '//img[contains(@data-galleryid, '+ photo_name +')]'))
                )
            except Exception, e:
                raise Exception(e)
        return True
    except Exception, e:
        print 'Failed to upload photo {}'.format(str(e))
        return False

edited May 31, 2017 at 19:23

answered Nov 29, 2016 at 18:10

sudo

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3 Comments

Netrix Over a year ago

I think this is some kind of buggy scenario, because there are two requests with single file instead of one with multiple files. In my case one request starts big machinery for all files. Do you know how to do it with one request?

sudo Over a year ago

@Netrix Not sure if your using the actual code I supplied but it does not have logic to determine if a photo with a specific name has already been uploaded, so hence why it would produce duplicates. I have edited my post to include such logic. Hopefully that answers your question.

Netrix Over a year ago

Thanks, but what I found out is that one call of send_keys produce one POST in my case. What I want is to be able to upload multiple files wit hone send_keys request. I found out how to do it but it probably uses a bug that keeps previously sent file for next request so when I call send_keys for second file it will actually send two files.

user3587178 · Accepted Answer · 2014-04-30 11:56:16Z

0

I tried this. uploader.send_keys 'path_to_file1'will upload file1 and when i try to upload file2,

exception is thrown saying "uploader" element cannot be interacted with

I did a uploader.is_enabled()

It gives me false

answered Apr 30, 2014 at 11:56

user3587178

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Comments

Usman Gani · Accepted Answer · 2020-05-10 19:47:18Z

0

I didn't test this code, but I think it should work

image_string = " ".join(images_array)
driver.find_element_by_class_name('PhotoInputFile').send_keys(image_string)
time.sleep(2)
driver.find_element_by_class_name("ButtonUploadPhotos").click()

answered May 10, 2020 at 19:47

Usman Gani

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Comments

Ricardo Valbuena · Accepted Answer · 2021-07-02 18:01:07Z

0

Try using this because for me works :

 @staticmethod
 def set_multiple_file_file():
   element = (INSERT_FILE)
   ROOT_DIR = your.path
   first_path = archive1.something
   second_path = archive2.something
   third_path = archive3.something
   element.send_keys(ROOT_DIR + first_path + ROOT_DIR + second_path + ROOT_DIR + third_path)

answered Jul 2, 2021 at 18:01

Ricardo Valbuena

514 bronze badges

1 Comment

Sven Eberth Over a year ago

Code-only answers are not particularly helpful. Please add some descriptions of how this code solves the problem.

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