How can I do simple check in the following scenario. This is my array:
[data] => Array ( [0] => blog ... )
This does not seem to be working:
if(isset($data[1]) != "page") {
do stuff here...
}
I need to check if key [1] is set and value not equal to "page"
if(isset($data) && isset($data[1]) && $data[1] != 'page') {
// do something
}
You may be thinking, "why isn't he checking if $data is an array?" Because it doesn't matter you can access strings from subscripts in PHP.
isset($data). there is no need to check if it is an array, but you can if you prefer. It won't throw an error.Isset only returns booleans so you cannot compare the result to the string 'page' you will need to make 2 separate checks.
Also i am not sure if you wanted to check if the first element had page or that the element at index 1 had page (php arrays start at 0 if you don't define).
But it should be at least something like if(isset(data[1]) && data[1] != 'page')
I found a better solution:
if(!array_search("page", $data)) {
// do stuff here
}
This works for me
You are doing it wrong because isset will return bool not the value of $data[1].
Anyways, you can try the approach below:
if(isset($data) && array_key_exists(1, $data) && $data[1] != "page")
do stuff here...
}
array_key_exist will return true if key 1 exists in $data array and then will compare the data[1] with string.
Notice: Undefined variable: data if data is not set.