how to sort NSArray of size strings in iOS?

Question

There is a NSSet which contains some size strings for products. I am trying to use the NSSortDescriptor to sort the array. since it sorts alphabetically, the result is not exactly right.

The code snippet is as below:

NSSet *set = [[NSSet alloc] initWithObjects:@"40", @"30", @"31", @"3XL", @"44", @"46", @"50", @"52", @"54", @"56", @"48", @"33", @"L", @"M", @"S", @"XL", @"XS", @"XXS",@"XXL",nil];
NSArray *sizeArray = [set allObjects];
NSSortDescriptor *sizeSort = [NSSortDescriptor sortDescriptorWithKey:@"self" ascending: YES];
NSArray *sortedArray = [sizeArray sortedArrayUsingDescriptors:@[sizeSort]];

NSLog(@"Set: %@ \n Sorted: %@", set, sortedArray);

The output is as follow:

Set: {( 46, 52, XL, XXS, 54, 48, 33, 44, 50, L, 40, M, S, 30, 56, XS, XXL, 3XL, 31 )} Sorted: ( 30, 31, 33, 3XL, 40, 44, 46, 48, 50, 52, 54, 56, L, M, S, XL, XS, XXL, XXS )

The desirable result should be (30, 31, 33, 40, 44, 46, 48, 50, 52, 54, 56, XXS, XS, S, M, L, XL, XXL, 3XL )

Is there any better way to sort like this?

Avt · Accepted Answer · 2014-05-05 09:24:43Z

NSSet *set = [[NSSet alloc] initWithObjects:@"40", @"30", @"31", @"3XL", @"44", @"46", @"50", @"52", @"54", @"56", @"48", @"33", @"L", @"M", @"S", @"XL", @"XS", @"XXS",@"XXL",nil];
NSArray *sizeArray = [set allObjects];

    NSArray *sizes = @[@"XXS", @"XS", @"S", @"M", @"L", @"XL", @"XXL", @"3XL"];
    NSArray *sortedArray = [sizeArray sortedArrayUsingComparator:^NSComparisonResult(NSString *obj1, NSString *obj2) {
        NSUInteger index1 = [sizes indexOfObject:obj1];
        NSUInteger index2 = [sizes indexOfObject:obj2];
        if (index1 == NSNotFound && index2 == NSNotFound) {
            return [@([obj1 intValue]) compare:@([obj2 intValue])];
        }
        else if (index1 == NSNotFound)
        {
            return NSOrderedAscending;
        }
        else if (index2 == NSNotFound)
        {
            return NSOrderedDescending;
        }
            return [@(index1) compare:@(index2)];
    }];

NSLog(@"Set: %@ \n Sorted: %@", set, sortedArray);

Output:

Set: ( 46, 52, XL, XXS, 54, 48, 33, 44, 50, L, 40, M, S, 30, 56, XS, XXL, 3XL, 31 )
Sorted: (30, 31, 33, 40, 44, 46, 48, 50, 52, 54, 56, XXS, XS, S, M, L, XL, XXL, 3XL )

TamilKing · Accepted Answer · 2014-05-05 09:29:21Z

1

Updated answer...

NSSet *set = [[NSSet alloc] initWithObjects:@"40", @"30", @"31", @"3XL", @"44", @"46", @"50", @"52", @"54", @"56", @"48", @"33", @"L", @"M", @"S", @"XL", @"XS", @"XXS",@"XXL",nil];
NSArray *sizeArray = [set allObjects];

NSMutableArray *numberArray, *charArray;
numberArray = [NSMutableArray array];
charArray = [NSMutableArray array];

BOOL valid;
NSCharacterSet *alphaNums = [NSCharacterSet decimalDigitCharacterSet];
NSCharacterSet *inStringSet; 

for (int i = 0 ; i < [sizeArray count]; i++)
{
    inStringSet = [NSCharacterSet characterSetWithCharactersInString:[sizeArray objectAtIndex:i]];
    valid = [alphaNums isSupersetOfSet:inStringSet];    

    if (valid)
        [numberArray addObject:[sizeArray objectAtIndex:i]];
    else
        [charArray addObject:[sizeArray objectAtIndex:i]];
}



NSSortDescriptor *sizeSort = [NSSortDescriptor sortDescriptorWithKey:@"self" ascending: YES];
NSSortDescriptor *sizeSort1 = [NSSortDescriptor sortDescriptorWithKey:@"self" ascending: NO];

NSArray *sortedArray1 = [numberArray sortedArrayUsingDescriptors:@[sizeSort]];
NSArray *sortedArray2 = [charArray sortedArrayUsingDescriptors:@[sizeSort1]]; // sort in descending order.

NSMutableArray *fullSortedArray = [NSMutableArray array];

[fullSortedArray addObjectsFromArray:sortedArray1];
[fullSortedArray addObjectsFromArray:sortedArray2];

    NSLog(@"Set = %@ \n Sorted = %@", set, fullSortedArray);

Hi check out this

OutPut:

Set = {( 46, 52, XL, XXS, 54, 48, 33, 44, 50, L, 40, M, S, 30, 56, XS, XXL, 3XL, 31 )} Sorted = ( 30, 31, 33, 40, 44, 46, 48, 50, 52, 54, 56, 3XL, L, M, S, XL, XS, XXL, XXS )

edited May 5, 2014 at 9:29

answered May 5, 2014 at 9:16

TamilKing

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4 Comments

chancyWu Over a year ago

the last part should be XXS, XS, S, M, L, XL, XXL, 3XL

TamilKing Over a year ago

@Chancy: What type of sort this.. there is no order in this.\

chancyWu Over a year ago

Yes, there are some free typing strings in the array.

TamilKing Over a year ago

@Chancy: I updated my answer. If you need any free typing use for loop and change order of the objects in sortedArray2.

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