Select and disable each input field within a form, wrapped in a table in jquery

Question

I am disabling a form based on a checkbox...

I am having trouble adding the disabled attribute.

here is what I got so far: HTML:

<table id="shipInfoTable">
  <tr>
   <td>Name:</td>
   <td><input type="text" name="name" /></td>
  </tr>
  ...
</table>

Javascript selector/attribute manipulation(jquery):

$("#shipInfoTable tbody tr td input").each(function(index, item){
    item.attr("disabled", true);
});

Chrome Dev Console error: Uncaught TypeError: Object #<an HTMLInputElement> has no method 'attr'

When I alert out the item within the .each() it alerts [object HTMLInputElement]

Not quite sure how to select the input element properly. What am I doing wrong?

Kobi · Accepted Answer · 2010-02-27 18:56:01Z

12

The function will not give you a jQuery object. It should be:

$("#shipInfoTable input").each(function(index, item){
    $(item).attr("disabled", true);
});

(note that I also simplified your selector, it still works)
If you aren't doing anything eles with each item, this will work as well:

$("#shipInfoTable input").attr("disabled", true);

answered Feb 27, 2010 at 18:56

Kobi

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1 Comment

Please note: in current versions of jQuery, this was changed to .prop("disabled", true). I'm pretty sure attr didn't do was was intended anyway.

Pointy · Accepted Answer · 2010-02-27 19:07:26Z

4

....

$("#shipInfoTable tbody tr td input").each(function(){
    $(this).attr("disabled", true);
});

Pointy

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answered Feb 27, 2010 at 18:58

Sarfraz

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Derek Adair · Accepted Answer · 2010-02-27 20:06:16Z

0

the issue is the lack of $() in the .each() function...

$("#shipInfoTable tbody tr td input").each(function(index, item){
    $(item).attr("disabled", true);
});

answered Feb 27, 2010 at 20:06

Derek Adair

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