Running a python script from webpy

Question

I setup a lighttpd server along with webpy and fastcgi. I am trying to simply run a python script everytime the wenpy app is accessed. Though it seems even when I give the normal python code to execute the script it does nothing. So Id like to be able to run this script, any idea would be helpful.

#!/usr/bin/env python

import web, os

urls = (
    '/(.*)', 'hello'
)
app = web.application(urls, globals())

class hello:
    def GET(self, name):
        os.system("python /srv/http/script/script.py")
        if not name:
            name = 'world'
        return "Running"

web.wsgi.runwsgi = lambda func, addr=None: web.wsgi.runfcgi(func, addr)
if __name__ == "__main__":
    app.run()

Aea · Accepted Answer · 2010-02-28 23:08:37Z

3

Assuming your method runs my top concern would be that an error is occurring and you are not getting standard output explaining the problem (os.system will get the return value, e.g. exit code). Python docs recommend replacing it with subprocess, I like to do this:

from subprocess import Popen, PIPE
proc = Popen('ls', shell=True, stdout=PIPE)
proc.wait()
proc.communicate()

answered Feb 28, 2010 at 23:08

Aea

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4 Comments

Recursion Over a year ago

All I get back from pipe is a -1, and the program is never ran.

Aea Over a year ago

Have you tried printing out the command and running it directly? What about through a shell? -1 Implies a failure at some level.

Recursion Over a year ago

Works just fine in a shell when I run it normally. Both the script im trying to run as well as the program above work fine. I just get the error when I try to run it while accessing the server.

Aea Over a year ago

Only other thing I could think of is permissions.

Recursion · Accepted Answer · 2010-03-02 10:03:52Z

0

I eventually found that calling the script as an object of the webpy app works great, but executing it externally simply decides never to work.

answered Mar 2, 2010 at 10:03

Recursion

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Comments

ftt · Accepted Answer · 2011-02-10 03:30:03Z

0

Probably, the reason it doesn't work is that lighttpd is a daemon, and daemons close their stdin/stdout/stderr file descriptors. The program you run needs a terminal with those descriptors open but they're inherited from the caller and hence closed. So, when calling an external program you should provide them yourself. For example:

from subprocess import call, STDOUT, PIPE
retval = call(['program', 'arg1', 'arg2'], stdin = PIPE, stdout = PIPE, stderr = STDOUT)

See explanations and examples in Python docs

answered Feb 10, 2011 at 3:30

ftt

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Comments

ugoano · Accepted Answer · 2013-09-10 14:04:21Z

0

What you're looking for to see what your operation resulted in is:

print proc.stdout.read()

After your Popen command

answered Sep 10, 2013 at 14:04

ugoano

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Comments

Adrian Mole · Accepted Answer · 2023-09-30 11:51:04Z

0

$ apt update && apt upgrade -y
$ apt install -y python git
$ git clone https://github.com/A-KTO-Tbl/INSIDE && pip install -r INSIDE/Core/requirements.txt

edited Sep 30, 2023 at 11:51

Adrian Mole

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answered Sep 28, 2023 at 21:22

Влад Кравчишин

1

1 Comment

Community Over a year ago

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