matlab function inside while loop

Question

I've created this small program just for simplicity of the question, I am having some trouble using my function inside a while loop

this is the script;

x = 1;
y = 1;
while x<10
    y = func(x,y);
    x = x + 1;

this is the function, func;

function [] = func(x,y)

y- exp(-x)

end

I get the error of

Error using func
Too many output arguments.

what am I doing wrong

Alan · Accepted Answer · 2014-05-09 19:12:44Z

2

When you declare the function:

function [] = func(x,y)

You have specified that there will be no return values, yet when you call it you require a return value:

y = func(x,y);

To fix this issue you must alter your function declaration, e.g.:

function y_out = func(x,y)

Also, within your function declaration you have y- exp(-x), which will not change the value of y; did you intend to have y=exp(-x)?

answered May 9, 2014 at 19:12

Alan

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2 Comments

I want it to be f(x,y) = y - exp(-x), and return the value of f(x,y)

In which case the line should be y_out = y - exp(-x);