Replacing items in nested array and list-tuple

Question

Good day to all.

I've been looking for a way to replace items within an array.

Basically I have an array with nested list that looks like that:

array = [ ('a', 'a'), 'c', ('c', 'a'), 'g', 'g', ('h', 'a'), 'a']

Now I'm looking for a way to replace all the appearances of 'a' with 'z'.

and I was hopping to use the following code line in order to achieve that:

new_array = [w.replace('a', 'z') for w in array]
new_array = [ ('z', 'z'), 'c', ('c', 'z'), 'g', 'g', ('h', 'z'), 'a']

Yet, unfortunately I'm receiving the following error:

AttributeError: 'tuple' object has no attribute 'replace'.

I understand the main problem is caused by the use of the tuple (a, x), but they're crucial part of the desired array.

I've spent hours looking for a way around it, And I would highly appreciate any hint in the right direction.

Your help is appreciated!

Python doesn't have arrays as a core data-structure - those are lists. — Gareth Latty
– Gareth Latty, Commented May 10, 2014 at 17:43
Tuples are immutable, either replace the entire tuple or use lists. — tmr232
– tmr232, Commented May 10, 2014 at 17:43

Johnny · Accepted Answer · 2014-05-10 17:55:04Z

3

def replace(value, find, rep):
    if isinstance(value, tuple):
        return tuple(rep if val==find else val for val in value)
    return value

new_array = [replace(val, 'a', 'z') for val in array]

the last ) should be ].

edited May 10, 2014 at 17:55

Johnny

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answered May 10, 2014 at 17:46

Daniel

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1 Comment

Padraic Cunningham Over a year ago

just need to replace ) with ] at the end of new_array = [replace(val, 'a', 'z') for val in array)

grdvnl · Accepted Answer · 2014-05-10 18:15:56Z

2

  array = [ ('a', 'a'), 'c', ('c', 'a'), 'g', 'g', ('h', 'a'), 'a']
  map(lambda l: tuple(i if i != 'a' else 'z' for i in l)  if isinstance(l, tuple) else l, array)

edited May 10, 2014 at 18:15

answered May 10, 2014 at 17:57

grdvnl

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