Convert binarystring to int, in C or C++ [duplicate]

Question

I have got a String filled up with 0 and 1 and would like to get an Integer out of it: (platform in an Arduino UNO)

String bitString = ""; 
int Number;
int tmp;

bitString = "";
  for (i=1;i<=10;i++)
  {
    tmp= analogRead (A0);
    bitString +=  tmp % 2;
    delay(50);
  }
// now bitString contains for example "10100110" 
// Number = bitstring to int <-------------
// In the end I want that the variable Number contains the integer 166

:/ I wasn't sure if all the libraries were available on that platform. — Sunny Patel
– Sunny Patel, Commented May 12, 2014 at 19:08
look at long strtol (const char String_Input[], char **End_Pointer, int Base); i.e. int num = strtol(bitString, NULL, 2); — ryyker
– ryyker, Commented May 12, 2014 at 19:15

ooga · Accepted Answer · 2014-05-12 19:14:28Z

1

You don't need a string of bits at all. Just do this:

  int n = 0;  // unsigned might be better here
  for (i = 0; i < 10; i++) {
    int bit = analogRead(A0) & 1;
    putchar('0' + bit);
    n = (n << 1) | bit;
    delay(50);
  }
  printf("\n%d\n", n);

edited May 12, 2014 at 19:14

answered May 12, 2014 at 19:04

ooga

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2 Comments

kimliv Over a year ago

looks like it does the job. how can I print out the binary string?

ooga Over a year ago

That depends. I'll edit the above to show one way.

user3629368 · Accepted Answer · 2014-05-12 19:12:52Z

1

you can use strtol() function :

#include <stdio.h>
#include <stdlib.h>

int main(int argc, const char * argv[])
{
char *a = "10100110";

int b = (int) strtol(a, NULL, 2);

printf("%d", b); //prints 166

return 0;
}

answered May 12, 2014 at 19:12

user3629368

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