Passing array variable to View in Codeigniter

Question

Good Day! I have this code and I don't know what could be the problem with my code 'casue I can't echo the value of variable in view.

This is my controller:

public function generate()
{
    $name    =   $this->input->post('name');

    $this->data['generated'] = $this->user_models->generate_name($name);
    $this->load->view('templates/header');
    $this->load->view('generated_user_views', $this->data);
    $this->load->view('templates/footer');
}

The Model:

function generate_name($name)
{
    $this->db->select('*');
    $this->db->from('user');
    $this->db->where('name', $name);
    $query = $this->db->get();

    return $query->result_array();
}

In View:

<?php
    $view_name = $generated['name'];
    $view_department = $generated['department'];
?>
<div class="form-group">
    <label for="name" class="col-sm-2 control-label emp">Name</label>
    <div class="col-sm-10">
        <input type="text" class="typeahead form-control" id="name" placeholder="Name" name="name" autocomplete="off"><?php echo $view_name; ?></input>
    </div>
</div>
<div class="form-group">
    <label for="department" class="col-sm-2 control-label emp">Department</label>
    <div class="col-sm-10">
        <input type="text" class="typeahead form-control" id="department" placeholder="Department" name="department" autocomplete="off"><?php echo $view_department; ?></input>
    </div>
</div>

I don't know why I always have an error like:

A PHP Error was encountered Severity: Notice Message: Undefined index: name Filename: views/generated_user_views.php Line Number: 12

A PHP Error was encountered Severity: Notice Message: Undefined index: department Filename: views/generated_user_views.php Line Number: 13

can you a post what is the value of $this->data before you pass it to the view? — Eddie
– Eddie, Commented May 13, 2014 at 6:46

M Khalid Junaid · Accepted Answer · 2014-05-13 06:46:47Z

1

In your model you are selecting all the data from your table so there is a multidimensional array returned,In view you need to loop over your results,see docs

foreach ($generated as $row)
{

   echo $row['name'];
   echo $row['department'];
}

Or i guess if you need a single record from your table then you can use $query->row_array();in your model and in view you can access them as

   $view_name =$generated['name'];
   $view_department = $generated['department'];

answered May 13, 2014 at 6:46

M Khalid Junaid

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Comments

Allen Chak · Accepted Answer · 2014-05-13 06:46:59Z

0

Try this:

$name = $this->input->post('name');
$department = $this->user_models->generate_name($name);

$this->data = array('generated' => array('name' => $name, 'department'=> $department);

answered May 13, 2014 at 6:46

Allen Chak

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1 Comment

Paul Over a year ago

method generate_name returns array from user table, not only department value

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