Objective-C insert Value at specfied index in mutlidimensional array

Question

I have three arrays and all are multidimensional.

What I want is:

Array1: 
id=[1,2,3]
name=[a,b,c]
price=[1,2,3]

Array2: 
id=[4,5,6]
name=[d,e,f]
price=[4,5,6]

Array3: 
id=[7,8,9]
name=[g,h,i]
price=[7,8,9]

So, how can i merge/combine the ID,Name and Price from array2 and array3, to array 1 so that I get this result:

Array1: 
id=[1,2,3,4,5,6,7,8,9]
name=[a,b,c,d,e,f,g,h,i]
price=[1,2,3,4,5,6,7,8,9]

I have to do it seperate. Or is it possible like this:

NSMutableArray *array = [[NSMutableArray alloc]initWithObjects:array1id aray2id array3id,array1name array2name array3name,array1price array2price array3price, nil];

Do each of the array contains a dictionary named id, name and price which contains another array? — Anoop Vaidya
– Anoop Vaidya, Commented May 21, 2014 at 9:46

Anoop Vaidya · Accepted Answer · 2014-05-21 11:09:45Z

1

You can do it using loops by :

NSMutableArray *mergeArray = [NSMutableArray new];

for (NSInteger i=0; i<3; i++) {
    NSMutableArray *tempArray = [NSMutableArray arrayWithArray:arr1[i]];
    [tempArray addObjectsFromArray:arr2[i]];
    [tempArray addObjectsFromArray:arr3[i]];
    [mergeArray addObject:tempArray];
}

NSLog(@"%@",mergeArray);

Edit:

The input is:

    NSArray *arr1 = @[@[@1,@2,@3],
                      @[@"a", @"b", @"c"],
                      @[@"A", @"B", @"C"]
                      ];
    NSArray *arr2 = @[@[@4,@5,@6],
                      @[@"d", @"e", @"f"],
                      @[@"D", @"E", @"F"]
                      ];
    NSArray *arr3 = @[@[@7,@8,@9],
                      @[@"g", @"h", @"i"],
                      @[@"G", @"H", @"I"]
                      ];

The output is :

( ( 1, 2, 3, 4, 5, 6, 7, 8, 9 ), ( a, b, c, d, e, f, g, h, i ), ( A, B, C, D, E, F, G, H, I ) )

edited May 21, 2014 at 11:09

answered May 21, 2014 at 10:12

Anoop Vaidya

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2 Comments

TdoubleG Over a year ago

Thaths not exactly what I want. The result should be a multidimensional array

TdoubleG Over a year ago

sorry you were right. I wrote wrong function. That worked very great thanks!

Matteo Gobbi · Accepted Answer · 2014-05-21 10:07:56Z

First of all you should to have 3 NSMutableDictionary with 3 NSArray in.

You can simply get an union from arrays by KVC Collection Operators:

NSArray *newArray = [@[array1, array2, array3] valueForKeyPath:@"@unionOfArrays.self"];

or if you don't want duplicate:

NSArray *newArray = [@[array1, array2, array3] valueForKeyPath:@"@distinctUnionOfArrays.self"];

So in your case should be something like:

NSMutableDictionary dict1 {
    id:NSArray,
    name:NSArray,
    price:NSArray
}

and so:

dict1[@"id"] = [@[dict1[@"id"], dict2[@"id"], dict3[@"id"]] valueForKeyPath:@"@unionOfArrays.self"];

Use this example to understand:

NSDictionary *dict1 = @{@"id":@[@1,@2,@3],@"name":@[@"a",@"b",@"c"]};

NSDictionary *dict2 = @{@"id":@[@4,@5,@6],@"name":@[@"d",@"e",@"f"]};

NSDictionary *dict3 = @{@"id":@[@7,@8,@9],@"name":@[@"g",@"h",@"i"]};

NSMutableDictionary *mDict = [NSMutableDictionary new];

mDict[@"id"] = [@[dict1[@"id"], dict2[@"id"], dict3[@"id"]] valueForKeyPath:@"@unionOfArrays.self"];
mDict[@"name"] = [@[dict1[@"name"], dict2[@"name"], dict3[@"name"]] valueForKeyPath:@"@unionOfArrays.self"];

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