SimpleXMLElement->array, in_array not working

Question

print_r($xml);:

SimpleXMLElement Object
(
    [groupId] => Array
        (
            [0] => 1
            [1] => 5
        )
)

in_array(1, $xml->groupId) on this doesn't work: PHP Warning: in_array() expects parameter 2 to be array, object given

print_r((array)$xml->groupId); prints only first element in array:

Array
(
    [0] => 1
)

How can I properly check for an element existing in groupId, without a hack like json_decode(json_encode($xml->groupId)); ?

XML print_r($xml->asXML());:

<?xml version="1.0"?>
<return>
    <groupId>1</groupId>
    <groupId>5</groupId>
    <code>13</code>
</return>

Why does (array)$xml->groupId .... oh ... lol :-) Now I see the problem.... thanks

can you also post your xml? try $xml->{groupId}

Rakesh Sharma
– Rakesh Sharma

2014-05-23 10:12:56 +00:00
Commented May 23, 2014 at 10:12 — Rakesh Sharma
– Rakesh Sharma, Commented May 23, 2014 at 10:12
see link this would be help you.

Satish Sharma
– Satish Sharma

2014-05-23 10:16:32 +00:00
Commented May 23, 2014 at 10:16 — Satish Sharma
– Satish Sharma, Commented May 23, 2014 at 10:16

Rakesh Sharma · Accepted Answer · 2014-05-23 10:51:15Z

1

try

$xml = '<?xml version="1.0"?><return><groupId>1</groupId><groupId>5</groupId>
    <code>13</code></return>';

$xml = simplexml_load_string($xml);
print_r($xml);
if(in_array(1, (array)$xml)) {
    echo 'got it';
}else {
    echo 'not get';
}

edited May 23, 2014 at 10:51

answered May 23, 2014 at 10:19

Rakesh Sharma

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3 Comments

Daniel W. Over a year ago

When I looked at the XML, I noticed it is not like I expected. (array)$xml was correct, not (array)$xml->groupId :-) Can you update the answer a little bit for me to accept, thank you.

Rakesh Sharma Over a year ago

@DanFromGermany thanks i am confused on my answer cause you have also a good ranking on stack

Daniel W. Over a year ago

No problem, I was confused too ;) Have a nice day

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