find using regex, in terminal

Question

Using the command bellow:

find ./stylesheets/sass/ -maxdepth 1 -type f -regextype posix-egrep -regex '[^_].+\.scss'

I get this:

./stylesheets/sass/_hero.scss
./stylesheets/sass/_article-type.scss
./stylesheets/sass/app.scss
./stylesheets/sass/_footer.scss
./stylesheets/sass/_grid-items.scss

and I wanted just:

./stylesheets/sass/app.scss

so my negation [^_] of underscore, does not work beacuse it tries to match at the very beginning of a path, I suppose, and not the filename itself.

How to solve this, keeping it flexible enough for any depth of dirs before the actual filename?

No, it's matching 1 character that's not a _, followed by more than one character that can be anything, followed by the extension. — Wooble
– Wooble, Commented May 25, 2014 at 0:05

that other guy · Accepted Answer · 2014-05-25 00:17:38Z

4

Just do it with -name:

find ... -name '[^_]*.scss'

Alternatively, if you insist on using -regex, make sure your not-underscore is only in the last component of the pathname:

find ... -regex '.*/[^/_][^/]*\.scss$'

answered May 25, 2014 at 0:17

that other guy

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2 Comments

branquito Over a year ago

great, could you tell me which one of these is more portable?

that other guy Over a year ago

The first one is POSIX, the second is not.

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