I got acces to a XML file with the following data:
<VertrekTijd>2014-05-26T11:15:00+0200</VertrekTijd>
I use the following code to read this data:
case "VertrekTijd": lblv1.Text = (nodelist2.InnerText); break;
I recieve this in my label:
2014-05-26T11:15:00+0200
How do i get only the:
11:15
I looked around here but i didn't find any results.
One option is to use parsed time data from DateTime:
var date = DateTime.Parse( "2014-05-26T11:15:00+0200", System.Globalization.CultureInfo.InvariantCulture);
var res = date.Hour + ":" + date.Minute;
Another way is direct parsing with regular expression:
var res = Regex.Match("2014-05-26T11:15:00+0200", @"\d{1,2}:\d{1,2}").Value;
Yet another way is to play with string.Split and similar, but I wouldn't do that if you care about you mental health...
You can parse your time into a DateTime object and then present it:
DateTime dateTime;
if (DateTime.TryParse("2014-05-26T11:15:00+0200", out dateTime))
{
lblv1.Text = string.Format("{0}:{1}", dateTime.Hour, dateTime.Minute);
}
