Get proper output from self var python

Question

What I'm trying to do: Output the value of a self.out var in a way that I can still use in another method.

The code

if self.path_object is not None:
    dictpath = {}
    for path in self.path_object:
        parsed = urlparse(path.pathToScan)
        if parsed.query:
            self.params = parsed.query.split('&', 2)
            self.out = list(map(lambda v: v.split("=")[0] +"=" + str(self.fooz), self.params))
            dictpath[parsed.geturl()] = self.out
    print dictpath

This code brings in a set of paths (via path_object), it then parses those paths on the & symbol and attaches the value of self.fooz to it, then puts it into a dictionary and outputs the results.

Result Its currently outputting a list like (added spacing for readability):

{
u'www.somesite.com/param.php?id=317':
    u'id=[<self.fooz>, <self.fooz>, <self.fooz>,<self.fooz>, <self.fooz>, <self.fooz>]', 

u'somesite.com/param.php?id=911&param2=6&param3=cat': 
    [u'id=[<self.fooz>, <self.fooz>, <self.fooz>,<self.fooz>, <self.fooz>, <self.fooz>]', 
    u'param2=[<self.fooz>, <self.fooz>, <self.fooz>,<self.fooz>, <self.fooz>, <self.fooz>]', 
    u'param3=[<self.fooz>, <self.fooz>, <self.fooz>,<self.fooz>, <self.fooz>, <self.fooz>]']
}

My question is, how can I access this output in another method, so that I can loop through each parameter like:

u'somesite.com/param.php?id=<<<<<self.fooz>>>>>&param2=6&param3=cat':

then

u'somesite.com/param.php?id=911&param2=<<<<<self.fooz>>>>>&param3=cat

and then so on for each parameter in a path.

So, far I have tried requesting a url from the present output, but requests isn't allowing a path to be requested like <self.fooz> as its not a valid url (e.g. including somesite.com or http://somesite.com).

Any help is greatly appreciated.

Thank you SO much!

pts · Accepted Answer · 2014-05-29 13:21:17Z

1

You have to parse the string again. Use urlparse.parse_qs (https://docs.python.org/2/library/urlparse.html). Do it like this:

import urlparse
s = u'somesite.com/param.php?id=911&param2=<<<<<self.fooz>>>>>&param3=cat'
params = urlparse.parse_qs(s[s.find('?') + 1:])
print params

The result is:

{u'param3': [u'cat'], u'id': [u'911'], u'param2': [u'<<<<<self.fooz>>>>>']}

Now you can iterate over params.

edited May 29, 2014 at 13:21

answered May 29, 2014 at 13:11

pts

88.7k25 gold badges117 silver badges203 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

CodeTalk Over a year ago

Thanks for the suggestion. Could you show an example in this case of how to go about this?

CodeTalk Over a year ago

I see how this is working now. I really appreciate it @pts ! Thanks!

Collectives™ on Stack Overflow

Get proper output from self var python

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related