Showing undefined variable when passing url variable in php

Question

I have two php pages and I want to pass variable value using URL while click on a hyperlink.

Code snip 1: movie1-rev01.php

<html>
<head>
<title>Find my Favorite Movie!</title>
</head>
<body>
<?php
echo "<a href='moviesite-rev03.php?favmovie=Stripes'>Click here to see movie</a>";
?>
</body>
</html>

Code snip 2: moviesite-rev03.php

<html>
<head>
<title>My Movie Site - <?php echo $favmovie; ?>
</title>
</head>
<body>
<?php
echo "My favorite movie is ";
echo $favmovie;
echo "<br>";
$movierate = 5;
echo "My movie rating for this movie is: ";
echo $movierate;
?>
</body>
</html>

When I click on the link on page movie1-rev01.php then it shows an error message "Undefined variable: favmovie in C:\wamp\www\solutions\moviesite-rev03.php"

Please help me out. I'm new in PHP.

@SomadderAbhijit if someone did helped you on this question, maybe you could repay them an upvote atleast or accept an answer — user1978142
– user1978142, Commented Jun 2, 2014 at 7:45

M D · Accepted Answer · 2014-06-02 12:31:10Z

1

You can do the same by

$_REQUEST['favmovie'] or $_GET['favmovie']

ie.

define some variable,
$va = $_REQUEST[''favmovie];
instead of  echo $favmovie;

edited Jun 2, 2014 at 12:31

M D

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answered Jun 2, 2014 at 6:23

user2638471

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1 Comment

M D Over a year ago

@ankit format your code properly so that code is understandable.

Jite · Accepted Answer · 2014-06-02 06:03:13Z

0

You are trying to access a GET variable in the second file.
Its not defined as $favmovie but $_GET['favmovie'].

answered Jun 2, 2014 at 6:03

Jite

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Comments

AeJey · Accepted Answer · 2014-06-02 06:03:15Z

0

You have to assign the get value to $favmovie;

Put

$favmovie = $_GET['favmovie'];

or

$favmovie = $_REQUEST['favmovie'];

at the top of the page or anywhere before using $favmovie

answered Jun 2, 2014 at 6:03

AeJey

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Comments

Vikas Arora · Accepted Answer · 2014-06-02 06:04:15Z

0

You have to use $_GET to fetch the url variables.

So, in your moviesite-rev03.php. Do like this:

<html>
<head>
<?php
   $favmovie = $_GET['favmovie'];
?>
<title>My Movie Site - <?php echo $favmovie; ?>
</title>
</head>
<body>
<?php
echo "My favorite movie is ";
echo $favmovie;
echo "<br>";
$movierate = 5;
echo "My movie rating for this movie is: ";
echo $movierate;
?>
</body>
</html>

Also, for a side note: If you are planning to use this variable for database query purpose, I suggest to you to look into removing sql injection

answered Jun 2, 2014 at 6:04

Vikas Arora

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Comments

ketan · Accepted Answer · 2014-06-02 06:42:48Z

0

First need to get variables that exists in url.. for that PHP provides several methods. In your case you can use GET.

you can use like this :

$favmovie = $_GET['favmovie'];

this will store value from variable(favmovie) in url and store it to $favmovie in that page.. now you can use $favmovie as you wish.

to display in page. use echo $favmovie; or echo $_GET['favmovie'];

for more info: http://www.php.net/manual/en/reserved.variables.get.php

edited Jun 2, 2014 at 6:42

ketan

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answered Jun 2, 2014 at 6:21

subashbasnet8

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