I am using selenium webdriver with Python on IE and the code mentioned below is working fine but I need to make this in a loop. Please suggest. termsName0 may be 2 ,3 4 or N numbers
Code:
Select(self.driver.find_element_by_name("termsName0")).select_by_visible_text("Blank No Text")
Select(self.driver.find_element_by_name("termsName1")).select_by_visible_text("Blank No Text")
Select(self.driver.find_element_by_name("termsName3")).select_by_visible_text("Blank No Text")
You can use try except contract if you do not know the "N".
from selenium.common.exceptions import ElementNotVisibleException, WebDriverException, NoSuchElementException
try:
i = 0
while True:
name = "termsName" + str(i)
Select(self.driver.find_element_by_name(name).select_by_visible_text("Blank No Text")
i +=1
except (ElementNotVisibleException, WebDriverException, NoSuchElementException):
pass
This is one way. N specifies how many times you want to loop
N = 4
for i in range(N):
name = "termsName" + str(i)
Select(self.driver.find_element_by_name(name).select_by_visible_text("Blank No Text")
Basically it takes the number of the current iteration and appends that to "termsName".
Above code is equivalent to
Select(self.driver.find_element_by_name("termsName0")).select_by_visible_text("Blank No Text")
Select(self.driver.find_element_by_name("termsName1")).select_by_visible_text("Blank No Text")
Select(self.driver.find_element_by_name("termsName2")).select_by_visible_text("Blank No Text")
Select(self.driver.find_element_by_name("termsName3")).select_by_visible_text("Blank No Text")
For iterating variable number of items you could try something like this
#To fetch all elements start with termsName
element_list = firefox_driver.find_elements_by_id("termsName[0-9]*")
# below code will iterate over the all links
for i in range(len(element_list)):
name = "termsName" + str(i)
Select(self.driver.find_element_by_name(name).select_by_visible_text("Blank No Text")
Hope it helps.
