php add a value to an array when a condition is met

Question

i'm still new to PHP so i need a suggestion on how am i able to add a value to an array corresponding a condition

 $single_items = array[]; //single item declaration
 $set_items = array[]; //set item declaration

 //fetch single items
 for($i = 0; $i < 10; $i++) {
      if($val[$i] !=0) {
           //insert $val[$i] to $single_items array
      }
 }

thanks in advance

John Conde · Accepted Answer · 2014-06-05 13:33:01Z

3

Just use [] syntax to add a value to an array (you can also use array_push()):

 $single_items = array(); //single item declaration
 $set_items = array(); //set item declaration

 //fetch single items
 for($i = 0; $i < 10; $i++) {
      if($val[$i] !=0) {
           //insert $val[$i] to $single_items array
           $single_items[] = $val[$i];
           // alternative
           // array_push($single_items , $val[$i]);
      }
 }

FYI, you had invalid syntax in your array variable declarations.

answered Jun 5, 2014 at 13:33

John Conde

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1 Comment

CudoX Over a year ago

so it can also be $single_items = []; ?

Rajendra Yadav · Accepted Answer · 2014-06-05 13:33:40Z

3

$single_items = array(); //single item declaration
$set_items = array(); //set item declaration

//fetch single items
for($i = 0; $i < 10; $i++) {
  if($val[$i] !=0) {
        $single_items[] = $val[$i];
       //insert $val[$i] to $single_items array
  }
}

answered Jun 5, 2014 at 13:33

Rajendra Yadav

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Comments

Hardik Patel · Accepted Answer · 2014-06-05 13:48:55Z

0

Try this :

  $single_items = array(); //single item declaration
 $set_items = array("Hardik", "Nirav", "Alpesh",5,"Shweta"); //set item declaration

 //fetch single items
 for($i = 0; $i < count($set_items); $i++) {
      if($set_items[$i] !=NULL) {
           //insert $val[$i] to $single_items array
           $single_items[$i] = $set_items[$i];
           echo $single_items[$i]."<br/>";
      }
 }

answered Jun 5, 2014 at 13:48

Hardik Patel

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